The number of presale tickets sold is 271
<em><u>Solution:</u></em>
Let "p" be the number of presale tickets sold
Let "g" be the number of tickets sold at gate
<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>
Therefore,
Presale tickets + tickets sold at gate = 800
p + g = 800 ------ eqn 1
<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>
Therefore,
Number of tickets sold at gate = twice the number of pre-sale tickets - 13
g = 2p - 13 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
p + 2p - 13 = 800
3p -13 = 800
3p = 800 + 13
3p = 813
p = 271
Thus 271 presale tickets were sold
Answer: 4 x − 7 = 2 4x-7=2 4x−7=2. Add 7 to both sides. Simplify 2 + 7 2+7 2+7 to 9. Divide both sides by 4.
Step-by-step explanation:
Answer:
adult tickets = 17, children tickets = 9
Step-by-step explanation:
Let x be the number of children and y the number of adults
Then given that 26 tickets are sold, we can write
x + y = 26 → (1)
Given that ticket cost was $194 we can write
5.5x + 8.5y = 194 → (2)
Rearrange (1) expressing y in terms of x by subtracting x from both sides
y = 26 - x → (3)
Substitute y = 26 - x into (2)
5.5x + 8.5(26 - x) = 194 ← distribute and simplify left side
5.5x + 221 - 8.5x = 194
- 3x + 221 = 194 ( subtract 221 from both sides )
- 3x = - 27 ( divide both sides by - 3 )
x = 9
Substitute x = 9 into (3) for corresponding value of y
y = 26 - 9 = 17
Hence number of adult tickets sold = 17
number of children tickets sold = 9
The domain would be (4, infinity) so most likely your answer would be D.
Answer:
7.72 * 10^15
Step-by-step explanation:
8*10^15 - 2.8*10^14 = 7.72 * 10^15
