Triangle inequality rule states that the sum of eachpair of sides must be greater than the third sides.
240 + 123 > 207 true
240 + 207 > 123 true
123 + 207 > 240 true
A = √(s(s-a)(s-b)(s-c))
s is the semi-perimeter (a + b + c)/2
s = (240 + 123 + 207)/2
s = 285
A = √(285*(285-249)(285-123)(285-207))
A = 12,730 units^2
Answer:
63*
Step-by-step explanation:
The first thing you need to do is find the value of x. What I did for this was trial and error. I tried a number, and if it was too big, I tried a smaller one. If you add up all of the angles, it should equal up to 180*, so I kept on doing this until I added up to 180.
The answer I got was x=8, so I plugged this into the equation for A and solved. 9x8 is 72, and 72-9 is 63.
Therefore, 63 is the correct answer.
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Answer:
c. Side-Angle-Side
Step-by-step explanation:
Two sides (AB and AC) and an included angle (<BAC) in triangle ∆ABC are congruent to two corresponding sides (AD and AC) and an included corresponding angle (<DAC) in ∆ADC.
Therefore, by the SAS Congruence Theorem, both triangles are congruent.
Answer:
73.1 inches
Step-by-step explanation:
We solve for this using z score formula.
z-score is z = (x-μ)/σ,
where x is the raw score,
μ is the population mean
σ is the population standard deviation.
x = unknown = randomly selected male's height
μ = 70.3 inches
σ = 4.1 inches
z = is not given but we are given its percentile which is 75
The z score for a 75th percentile = 0.674
Hence,
0.674 = x - 70.3/4.1
Cross Multiply
0.674 × 4.1 = x - 70.3
2.7634 = x - 70.3
x = 70.3 + 2.7634
x = 73.0634 inches
The height of the randomly selected male = 73.0634
Therefore, the height of the randomly selected male to the nearest tenth of an inch is 73.1 inches