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3 years ago

What plus 432 equals 512

Mathematics

2 answers:

kakasveta [241]3 years ago

5 0

Answer:

Step-by-step explanation:

just subtract 432 from 512 and you get 80 then u can add 80 to 432 and check and see that it is 512 which it is

beks73 [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Subtract 512 and 432

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romanna [79]

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3 years ago

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OLga [1]

The set of numbers in the Collatz Conjecture are 1, 4, 2, 1, 4, 2, 1, 4, 2....

<h3>How to generate the numbers in the Collatz Conjecture</h3>

To start with, we make use of the following starting point:

Starting point = 1

The rule is given as:

If the last number is odd, multiply it by 3 and add 1.
If the last number is even, divide the number by 2.

1 is an odd number.

So, we use the first rule

So, we have:

1 * 3 + 1 = 4

4 is an even number.

So, we use the second rule

So, we have:

4/2 = 2

So, the first three numbers in the Collatz Conjecture are:

1, 4, 2

Using the given rules, we have:

1, 4, 2, 1, 4, 2, 1, 4, 2....

The above means that there is only one set of repeating numbers in the Collatz Conjecture.

Hence, the set of numbers in the Collatz Conjecture are 1, 4, 2, 1, 4, 2, 1, 4, 2....

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brainly.com/question/7882626

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5 0

2 years ago

There are 3 red marbles and 8 blue marbles in a bag.

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3 years ago

Please answer! this is an important exam that im taking right now.

Scorpion4ik [409]

Answer:

Required ordered pair is (0,0) for system of equation

Step-by-step explanation:

The given system of equation is

A). $9^{12x} = 9^{3y}$

B). $y^{4} - 9y^{2} x^{2} =16y$

On simplifying the equation A

$9^{12x} = 9^{3y}$

Take log on both side,

(12x) (log9) = (3y) (log9)

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To find the solution of the system of the equation :

Replacing value of y=4x in equation B,

$y^{4} - 9y^{2} x^{2} =16y$

$(4x)^{4} - 9(4x)^{2} x^{2} =16(4x)$

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$256x^{4} - 144x^{4}=64x$

$112x^{4}=64x$

We get,

x=0 and x=0.829

Since, 0.829 is not integer number

Only solution of equations is x=0

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Replace value x in y=4x=0

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How to calculate the percentage?

miv72 [106K]

$\: \: \: \: \:$

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<h2>hope it helps</h2>

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