Y=ln(ln(x))
y'=(1/x)/Ln(x)=1/xln(x)
Answer:
-5/2+-1/2√37≤x≤-5/2+1/2√37
Step-by-step explanation:
Step 1: Find the critical points
-x^2-5x+3=0
For this equation: a=-1, b=-5, c=3
−1x^2+−5x+3=0
x=−b±√b2−4ac/2a
x=−(−5)±√(−5)2−4(−1)(3)/2(-1)
x=5±√37
/−2
x=-5/2+1/2√37
Step 2: Check intervals in between critical points
x≤-5/2+1/2 √37 (Doesn't work in original inequality)
-5/2+-1/2√37≤x≤-5/2+1/2√37 (Works in original inequality)
x≥-5/2+1/2 √37 (Doesn't work in original inequality)
More than means to add.
Quotient means to divide.
4 + (12/x)
Answer:
Solution one is correct and solution 2 and 3 are incorrect
Step-by-step explanation:
You simply make an equation because for vertical angles 2 angles that are across from each other have the same value (in this case 2x+30 and 5x-36.)
The equation: 2x+30=5x-36---->3x=66----> x=22
Solution 1 is correct.
Hope this helped!
