Hardest one yet.. complete all of these i mean all of em
1 answer:
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Answer:
The turns of a graph is represented by the number of maximum or minimum that the function has.
If we differenciate f(x) we get:
f'(x)=4x^3+6x
f'(x)=2x(2x^2 + 3)
Therefore f'(x) =0, when x=0. Given that negative roots are not defined.
Therefore, the number of turns will be given by the number of solutions of f'(x) which is 1.
Attached you find the graph of the function which confirms the number of turns.
If the function had other solutions, the maximum number of turns it could have is 3! because f'(x) is a third degree polynomial, therefore it can't have more than 3 solutions!
Answer:
Step-by-step explanation:
<u><em>The question in English is </em></u>
An expanding mobile phone company handled eight hundred and fifty thousand calls a day during the quarter. In the next quarter it expects to reach one million and increase quarterly by the same amount over the next two years. How many daily calls do you expect to handle in two years?
Let
x ----> the number of quarter
y ---> number of daily calls
we know that
we have the points
(0,850,000) and (1,1,000,000)
Find the slope m
The linear equation that represent this situation is
How many daily calls do you expect to handle in two years?
In two years there are 8 quarterly
so
For x=8
substitute