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3 years ago

What is 2906 to the nearest thousand

Mathematics

2 answers:

boyakko [2]3 years ago

8 0

Round to nearest thousand should be 3000

OlgaM077 [116]3 years ago

3 0

It is equal to 3000 to the nearest thousandth

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What is the sum? 3k/k^2+k-7/4K

Aleksandr-060686 [28]

Answer:

$\dfrac{k^2+5k}{4k^2}$

Step-by-step explanation:

A suitable common denominator is 4k^2. (This eliminates the first and last choices.)

$\dfrac{3k}{k^2}+\dfrac{k-7}{4k}=\dfrac{4(3k)}{4(k^2)}+\dfrac{k(k-7)}{k(4k)}\\\\=\dfrac{12k+k^2-7k}{4k^2}=\boxed{\dfrac{k^2+5k}{4k^2}}$

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3 years ago

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3 years ago

Help me please! Am horrible at math.

lesya692 [45]

Answer:

Step-by-step explanation:

For a. the 14.7 represents the pressure that the air puts on you all the time.

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3 years ago

Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16

IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form $a_n=a_1+(n-1)d$ , where,

$a_n$ = nth term of sequence,

$a_1$ = 1st term of sequence,

n = Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

$\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}$

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

$1$

Let us solve for n.

$1$

$1\cdot \frac{16}{3}$

$5.333$

$n>5.333$

We can also write next terms of our sequence as:

$\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}$

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

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3 years ago