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Studentka2010 [4]
3 years ago
15

What are the sum of "j+5m"

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0
You can’t really find the sum unless there is number to plug in for the variables.
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Can’t afford to get wrong please do not write if you don’t know thanks !
Katena32 [7]
You don't need to understand the construction or why it works. You only need to accept the fact that it does. You can figure out the answers to this question by looking at the picture.

RT is tangent to circle Q -- TRUE. That is the point of the construction.

QT is a radius of circle Q -- TRUE. Q is the center and T is on the circle. A line segment from the center to a point on the circle is a radius.

m∠QSR = 90° -- FALSE. Those points lie on the same line. The measure of the angle is 180°.

QS = QT -- FALSE. S lies inside circle Q, so is closer to the center than T, which lies on the circle. (For some choice of point R, S might lie on the circle, but because this statement is not always true, it must be considered false.)

ΔRTQ is a right triangle -- TRUE. A tangent line is always perpendicular to the radius to the point of tangency. The construction succeeds because RTQ is inscribed in semicircle RTQ (centered at S). Such a triangle is always a right triangle.
3 0
4 years ago
FREE BRAINLY AND 50 PTS!! MIGHT BE EASY
Thepotemich [5.8K]
> and = with line through it
8 0
3 years ago
Read 2 more answers
3y=-6x+1 solve for y
Romashka [77]

Answer:

y= 2x +1/3

Step-by-step explanation:

3y= 6x+1

divide the whole equation by 3 to isolate y

y= 2x+1/3

6 0
3 years ago
Find the area of a circle with the radius of 73 feet
White raven [17]

Answer:

Step-by-step explanation:

area of a circle=πr^2

=3.14*(73)^2

=3.14*5329

=16733.06 ft^2

8 0
3 years ago
Read 2 more answers
The maximum load that a cylindrical column with a circular cross section can hold varies directly as the fourth power of the dia
kifflom [539]

Answer:

2396

Step-by-step explanation:

Let the diameter = d

Let the height = h

Formula

Metric Tons = k * d^4 / h^2

Solution

Metric Tons = 64

d = 2

h = 9

k = ?

(You can't do the second part by not using a ratio unless you  put k in and solve for it)

64 = 2^4 k / 9^2

64 = 8 *k / 81

64 * 81 / 8 = k

5184 / 8 = k

k = 648

Solve for the second example

Metric Tons = d^4 * k / h^2

Metric Tons = ?

d = 5

h = 13

k = 648

Metric Tons = 5^4 * 648 / 13^2

Metric Tons = 625 * 648 / 169

Metric Tons = 2396 rounded.

7 0
3 years ago
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