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stealth61 [152]
2 years ago
5

See figure in triangle PQR,ANGLE PQR=90°,segQS seg PR find x,y and z

Mathematics
1 answer:
e-lub [12.9K]2 years ago
3 0

Answer:

x=4√5

y=12

z=6√5

is your answer look it once

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Geometry geometry geometry help help
Leokris [45]

Answer:

what is it asking you? don't just show the problem tell us what needs to be done.

5 0
3 years ago
Read 2 more answers
The formula s= sqrt SA/6
ikadub [295]
For this case we have the following equation:
 s = root (S.A / 6)
 Substituting values we have:
 For S.A = 180:
 s = root (180/6)
 s = root (30)
 For S.A = 120:
 s = root (120/6)
 s = root (20)
 s = root (4 * 5)
 s = 2 * root (5)
 Subtracting both values we have:
 root (30) - 2 * root (5)
 Answer:
 
root (30) - 2 * root (5)
 
option 2
3 0
3 years ago
Simplify -9(1-10n) - 2(3n+9)
agasfer [191]

Answer:

3 (28 n - 9)

Step-by-step explanation:

Simplify the following:

-9 (1 - 10 n) - 2 (3 n + 9)

-9 (1 - 10 n) = 90 n - 9:

90 n - 9 - 2 (3 n + 9)

-2 (3 n + 9) = -6 n - 18:

90 n + -6 n - 18 - 9

Grouping like terms, 90 n - 6 n - 18 - 9 = (90 n - 6 n) + (-9 - 18):

(90 n - 6 n) + (-9 - 18)

90 n - 6 n = 84 n:

84 n + (-9 - 18)

-9 - 18 = -27:

84 n + -27

Factor 3 out of 84 n - 27:

Answer: 3 (28 n - 9)

4 0
3 years ago
Solve this system of equations by graphing. First graph the equations, and then type the solution.
tiny-mole [99]
Here the graph and what else you need

7 0
3 years ago
Find the probability of drawing 3 Aces at random from a deck of 52 ordinary playing cards if the cards are:_________
Minchanka [31]

Answer:

A) 1/2197

B) 1/5525

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome.

Since there are 52 random cards in a deck of card, the total outcome will be 52.

a) Also in a deck of card, there are 4 aces. If we are to select 3 aces with replacement, this means that each time we pick up an ace from the card, it was returned.

Pr(drawing an ace) = 4/52

Pr(drawing 3 aces and replacing it) = 4/52 *4/52*4/52

Pr(drawing 3 aces and replacing it) = 64/140,608

Pr(drawing 3 aces and replacing it) = 1/2197

b) If we pick 3 aces without replacement then each time we pick an ace, the total number cards keeps reducing.

Pr(picking the first ace) = 4/52

Pr(picking the second ace without replacing) = 3/51 (Since we didn't replace the first one, the total ace in the deck of card will reduce to 3 and the total will be 51)

Pr(picking the third ace without replacing) = 2/50 (since we didn't replace the first two aces, the total ace in the deck of card will reduce to 2 and the total will be 50)

Pr(drawing 3 aces without replacement) =  4/52*3/51*2/50

Pr(drawing 3 aces without replacement) =  24/132,600

Pr(drawing 3 aces without replacement) = 1/5525

5 0
3 years ago
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