hi
first case is : 2^0 = 1 , then each case is 2^(n-1) where "n" is the number of the case.
so case 3 is 2^(3-1) = 2^2 = 4 and case 64 is 2^(64-1) = 2^63
A) 26 + 18 = D
Where D = Dad's age.
B) No it isn't. You solve the above equation and it equals 44.
C) The first age comparison is 26 years apart, both going up by 8 each time, so by adding 8 to 36, it equals 44, which isn't 42.
y= x + 2 and y = x^2 - 4
Substitute mx + b for y
x^2 - 4 = x + 2
Solve for x
x^2 - 4 = x + 2
x^2 - x - 6 = 0
(x - 3)(x + 2) = 0
x - 3 = 0; x = 3
x + 2 = 0; x = -2
Substitute the first x value into the linear equation and solve for y
y = 3 + 2
y = 5
One solution is (3, 5)
Substitute the second x value into the linear equation and solve for y
y = -2 + 2
y = 0
Another solution is (-2 , 0)
Answer: 9
Step-by-step explanation:
I might be able to. post them and lets see
