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uysha [10]
3 years ago
5

M/s2

Physics
2 answers:
mestny [16]3 years ago
8 0

Answer:

Resultant netforce= mass x acceleration

Explanation:

Fnet is directly proportional to acceleration, and inversly proportinal to mass.

SCORPION-xisa [38]3 years ago
6 0

Answer:

resultant force = mass × acceleration

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A car slows down uniformly from a speed of 22 m/s to rest in 4.0 seconds. How far did it travel in that time
krek1111 [17]

Answer:

\boxed{\sf Distance \ travelled = 44 \ m}

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\boxed{ \bold{s =  (\frac{v + u}{2} )t}}

By substituting value of v, u & t in the equation we get:

\sf \implies s = ( \frac{0 + 22}{2} ) \times 4 \\  \\  \sf \implies s =  \frac{22}{2}  \times 4 \\  \\  \sf \implies s = 11 \times 4 \\  \\  \sf \implies s = 44 \: m

\therefore

Distance travelled by car (s) = 44 m

4 0
4 years ago
The water that powers the generators enters and leaves the system at a low speed (thus we can neglect its change of kinetic ener
madam [21]

Answer:

Explanation:

Let density of water be ρ .

During flow , volume of water flowing per second is constant

loss of P. E per unit volume  = ρ gh , 83.5 % is lost

Gain of K E per unit volume = 1/2  ρ v²

83.5 % of mgh =   ρ 1/2  ρ v²

1/2  ρ v² =  .835 x 9.8

v² =  2 x .835 x 9.8

= 16.366

v = 4.04 m /s

4 0
4 years ago
Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba
Allushta [10]
The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
p_i = p_1-p_2 = mv-mv =0
So, the final momentum must be zero as well:
p_f = 0
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
p_f = mv_1 + mv_2 = 0
From which
v_1 = -v_2

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is \frac{1}{2} mv^2. Therefore, the total kinetic energy before the collision is
K_i = \frac{1}{2} mv^2 +  \frac{1}{2} mv^2 = mv^2
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
K_f = K_i = mv^2 (1)
But the final kinetic energy, Kf, is also
K_f =  \frac{1}{2} mv_1^2 +  \frac{1}{2}mv_2^2
Substituting v_1 = -v_2 as we found in the conservation of momentum, this becomes
K_f = mv_2 ^2
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write 
mv_2^2 = mv^2

Therefore, the two final speeds of the balls are
v_2 = v
v_1 = -v_2 = -v

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

8 0
3 years ago
What organism would be at the top of the energy pyramid
gregori [183]
The answer could be B. Reef shark
7 0
3 years ago
Equation of motion description is v=20+2t.How big is the initial speed,acceleration?
trasher [3.6K]

Answer:

the initial velocity is 20 m/s   and  the acceleration is 2 m/s²

Explanation:

Given equation of motion, v = 20 + 2t

If V represents the final velocity of the object, then the initial velocity and acceleration of the object is calculated as follows;

From first kinematic equation;

v = u + at

where;

v is the final velocity

u is the initial velocity

a is the acceleration

t is time of motion

If we compare  (v = u + at)   to     (v = 20 + 2t)

then, u = 20    and  

         a = 2

Therefore, the initial velocity is 20 m/s   and  the acceleration is 2 m/s²

4 0
3 years ago
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