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alex41 [277]
3 years ago
15

Equation of motion description is v=20+2t.How big is the initial speed,acceleration?

Physics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

the initial velocity is 20 m/s   and  the acceleration is 2 m/s²

Explanation:

Given equation of motion, v = 20 + 2t

If V represents the final velocity of the object, then the initial velocity and acceleration of the object is calculated as follows;

From first kinematic equation;

v = u + at

where;

v is the final velocity

u is the initial velocity

a is the acceleration

t is time of motion

If we compare  (v = u + at)   to     (v = 20 + 2t)

then, u = 20    and  

         a = 2

Therefore, the initial velocity is 20 m/s   and  the acceleration is 2 m/s²

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Answer:

Q = q_e = 1.6 \times 10^{-19} C

Explanation:

As we know that charge is always conserved

so here we have

initial total charge = final total charge

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3 years ago
I NEED PHYSICS HELP? THE QUESTION IS IN THE PIC
Marina CMI [18]

Speed of the block at the bottom of the incline: 5.42 m/s

The first part of the problem can be solved by using the law of conservation of energy. Since the ramp is frictionless, the initial gravitational potential energy of the block at the top of the ramp is converted into kinetic energy at the bottom:

mgh = \frac{1}{2}mv^2 (1)

where

m is the mass of the block

g = 9.8 m/s^2 is the acceleration of gravity

h is the initial height of the block

v is the speed of the block at the bottom

The initial height of the block is equal to the height of the ramp, so

h=L sin \theta (2)

where

L = 3.00 m is the length of the ramp

\theta=30^{\circ} is the angle of the ramp

Substituting (2) into (1) and re-arranging the equation, we  find the speed

2gL sin \theta = v^2

v=\sqrt{2gL sin \theta}=\sqrt{2(9.8)(3.00)sin 30^{\circ}}=5.42 m/s

Coefficient of kinetic friction between the floor and the block: 0.3

In the second part of the motion, the block is slowed down by friction along the flat surface. According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the block:

W=\Delta K=K_f -K_i

where

W is the work done by friction

Kf is the final kinetic energy of the block, which is zero since the block comes to rest

K_i = \frac{1}{2}mv^2 is the initial kinetic energy of the block, where

m = 10.0 kg is the mass of the block

v = 5.42 m/s is its initial speed

Substituting into the equation, we find

W=-\frac{1}{2}mv^2=-\frac{1}{2}(10.0)(5.42)^2=-146.9 J

and the work is negative, since the direction of the force of friction is opposite to the direction of motion of the block.

Now we can rewrite the work as the product between the force of friction and the displacement of the block:

W=-F_f d = - \mu mg d

where

\mu is the coefficient of friction

d = 5.00 m is the displacement of the block

Solving for \mu,

\mu = - \frac{W}{mgd}=-\frac{-146.9}{(10.0)(9.8)(5.00)}=0.3

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