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adoni [48]
3 years ago
9

The ideal constant has a value of 0.0821 as long as the units for the other variables are...

Chemistry
1 answer:
Alex3 years ago
4 0

Answer:

Option D. atm, L, K, mole

Explanation:

To know which option is correct, do the following:

We shall use the standard value for each variable to obtain the gas constant. This can be obtained as follow:

Volume (V) = 22400 mL

Pressure (P) = 760 mmHg

Number of mole (n) = 1 mole

Temperature (T) = 273 K

Gas constant (R) =?

PV = nRT

R = PV / nT

R = (760 × 22400) / (1 × 273)

R = 62358.97 mmHg.mL/Kmol

Volume (V) = 22.4 L

Pressure (P) = 760 mmHg

Number of mole (n) = 1 mole

Temperature (T) = 273 K

Gas constant (R) =?

PV = nRT

R = PV / nT

R = (760 × 22.4) / (1 × 273)

R = 62.359 mmHg.L/Kmol

Volume (V) = 22400 mL

Pressure (P) = 1 atm

Number of mole (n) = 1 mole

Temperature (T) = 273 K

Gas constant (R) =?

PV = nRT

R = PV / nT

R = (1 × 22400) / (1 × 273)

R = 82.05 atm.mL/Kmol

Volume (V) = 22.4 L

Pressure (P) = 1 atm

Number of mole (n) = 1 mole

Temperature (T) = 273 K

Gas constant (R) =?

PV = nRT

R = PV / nT

R = (1 × 22.4) / (1 × 273)

R = 0.0821 atm.L/Kmol

From the above illustrations, we can see that the gas constant will have a value for 0.0821 as long as other variables are: atm, L, K, mole

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In the balanced equation , CS2 + 3O2 = CO2 + 2SO2 , how many mol of O2 would react with 34.5 mol of CO2?
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<u>Given:</u>

Moles of CS2 (it cannot be CO2 as mentioned in the question, since O2 reacts with CS2 and not CO2) = 34.5 mol

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