Question

In the balanced equation , CS2 + 3O2 = CO2 + 2SO2 , how many mol of O2 would react with 34.5 mol of CO2?

Answer 1

Given:

Moles of CS2 (it cannot be CO2 as mentioned in the question, since O2 reacts with CS2 and not CO2) = 34.5 mol

To determine:

Moles of O2 undergoing the reaction

Explanation:

The reaction is-

CS2 + 3O2 → CO2 + 2SO2

Based on the stoichiometry: 3 moles of O2 reacts with 1 mole of CS2

therefore the moles of O2 that would combine with 34.5 moles of CS2 are

= 3 moles O2 * 34.5 moles CS2/1 mole CS2 = 103.5 moles

Ans: Around 104 moles of O2 would react with 34.5 moles of CS2

Answer 2

Answer:

The moles of oxygen gas will react with 34.5 moles of carbon disulfide is 103.5 moles.

Explanation:

$CS_2+3O_2\rightarrow CO_2+2SO_2$

Given ,moles of carbon disulfide = 34.5 moles

According to reaction, 1 mol of carbon disulfide reacts with 3 moles of oxygen gas.

Then 34.5 moles of carbon disulfide will react with:

$\frac{3}{1}\times 34.5mol=103.5 mol$ oxygen gas.

The moles of oxygen gas will react with 34.5 moles of carbon disulfide is 103.5 moles.