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3 years ago

Sodiun atom, potassium atom, and cesium atoms have the same ?

Chemistry

2 answers:

Gemiola [76]3 years ago

5 0

Answer:

They have similar chemical properties

Explanation:

Hi, those elements all belong to the Group I of the periodic table meaning that they share not only similar electronic configuration (1 electron of valence) but also they have similar chemical properties, being those more marked the higher the atomic number.

An example of that shared properties is that all of them react violently with water, being cesium the most violent.

Tpy6a [65]3 years ago

3 0

Sodium atom , potassium atom and cesium atom have the same group number which is group 1

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Enthalpy change is the

PtichkaEL [24]

Answer:

I believe is A

Explanation:

Enthalpy change is the name given to the amount of heat evolved or absorbed in a reaction carried out at constant pressure.

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3 years ago

What do acid formulas have in common?

maks197457 [2]

the answer is H is the cation

Explanation :

The general formula of an acid is represented as, in which 'H' is hydrogen cation and 'X' is a non-metal or a poly-atomic anion.

For example : etc.

All the acids produces hydrogen ion, in an aqueous solution while the base produces hydroxide ion, in an aqueous solution.

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3 years ago

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The gaseous product of a reaction is collected in a 25.0L container at 27.0 C. The pressure in the container is 3.0atm and the g

NeX [460]

Answer: The molar mass of the gas is 31.6 g/mol

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 3.0 atm

V = Volume of gas = 25.0 L

n = number of moles = ?

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $27.0^0C=(27.0+273)K=300K$

$n=\frac{PV}{RT}$

$n=\frac{3.0atm\times 25.0L}{0.0821 L atm/K mol\times 300K}=3.04moles$

Moles = $\frac{\text {given mass}}{\text {Molar mass}}$

$3.04=\frac{96.0g}{\text {Molar mass}}$

${\text {Molar mass}}=31.6g/mol$

The molar mass of the gas is 31.6 g/mol

4 0

2 years ago

A cylinder with a moveable piston contains 92g of Nitrogen. The external pressure is constant at 1.00 atm. The initial temperatu

Jobisdone [24]

Answer:

Work done in this process = 4053 J

Explanation:

Mass of the gas = 0.092 kg

Pressure is constant = 1 atm = 101325 pa

Initial temperature $T_{1}$ = 200 K

Final temperature $T_{2}$ = 200 - 85 = 115 K

Gas constant for nitrogen = 297 $\frac{J}{kg k}$

When pressure of a gas is constant, volume of the gas is directly proportional to its temperature.

⇒ V ∝ T

⇒ $\frac{V_{2} }{V_{1} }$ = $\frac{T_{2} }{T_{1} }$ ------------ ( 1 )

From ideal gas equation $P_{1}$ $V_{1}$ = m R $T_{1}$ ------ (2)

⇒ 101325 × $V_{1}$ = 0.092 × 297 × 200

⇒ $V_{1}$ = 0.054 $m^{3}$

This is the volume at initial condition.

From equation 1

⇒ $\frac{V_{2} }{0.054}$ = $\frac{200}{115}$

⇒ $V_{2}$ = 0.094 $m^{3}$

This is the volume at final condition.

Thus the work done is given by W = P [ $V_{2}$ - $V_{1}$ ]

⇒ W = 101325 × [ 0.094 - 0.054]

⇒ W = 4053 J

This is the work done in that process.

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3 years ago

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Aleonysh [2.5K]

Answer:

Explanation:

it is corundum now please follow me

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3 years ago

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