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Sergeeva-Olga [200]
3 years ago
13

(17-12)+4×7 =? please xplain how you got the answer

Mathematics
2 answers:
expeople1 [14]3 years ago
7 0

Answer:

33

Step-by-step explanation:

i use cal

notka56 [123]3 years ago
5 0

Answer:

33

Step-by-step explanation:

(17-12)+4×7 (PEMDAS states we do the equation in the paranthesis 1st)

5 + 4*7     (We then multiply 4*7  because M comes before A)

5 + 28       (Then we just add)

33

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Find K' if the figure is reflected across the x-axis
snow_lady [41]
<h3>Answer:  K ' is at (1, 4)</h3>

Explanation:

Point K is located at (1, -4)

We use the rule that (x,y) \to (x,-y) when reflecting over the x axis.

The x coordinate stays the same, but the y coordinate flips from positive to negative or vice versa.

Therefore, K(1,-4) will move to K ' (1, 4)

5 0
2 years ago
Please help I need help with this question
denpristay [2]

Answer:

2.5% and 2.5 · 10^-3, 0.25, 2/5, √5

Step-by-step explanation:

0.25, 2/5, 2.5 · 10^-3, 2.5%, √5

Now let's list them all in the same form, why not decimals.

0.25 = 0.25

2/5 = 4/10 = 40/100 = 0.4

2.5 · 10^-3 = 2.5 · 0.01 = 0.025

2.5% = 0.025

√5 ≅ 2.236

5 0
2 years ago
What is the value of this expression?<br> 49 - (11 – 4)
Illusion [34]

Answer:

42

Step-by-step explanation:

11 - 4 = 7

49 - 7 = 42

3 0
3 years ago
Read 2 more answers
Please help me ASAPP
swat32
Answer:

I believe the answer is, A.

Explanation:

Ordered pairs are classified as a function when none of the x’s in the ordered pairs match.

Like in b, a pair has 3.
And in c, two pairs have 1 and 3.
7 0
2 years ago
The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i
kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

S=\pi r\sqrt{r^2+h^2}

and volume,

V=\frac{1}{3}\pi r^2 h

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

f(r,h)=\frac{1}{3}\pi r^2 h

subject to,

g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)

We know for maximum volume r\neq 0. So let \lambda be the Lagranges multipliers be such that,

f_r=\lambda g_r

\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)

And,

f_h=\lambda g_h

\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}

\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)

Substitute (3) in (2) we get,

\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)

\implies h^2=2r^2

Substitute this value in (1) we get,

\pi r\sqrt{h^2+r^2}=8

\implies \pi r \sqrt{2r^2+r^2}=8

\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252

Then,

h=\sqrt{2}(1.21252)\equiv 1.71476

Hence largest volume,

V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114

3 0
3 years ago
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