An aqueous solution contains
1 answer:
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Answer: 5.72 g mass of carbon dioxide was produced
Explanation:
Moles of C =
Mass of reacted = 59.1 g - 17.5 g = 41.6 g
Moles of
According to reaction 1 mole produces 1 mole of
then 1.3 mole of
will produce
moles of
Mass of :
=Moles of × molar mass of
= 1.3 ×44 g/mol =
=57.2 grams
5.72 g mass of carbon dioxide was produced
The equation for this question could be →
.
so for 6.75 moles of *3 moles of O_{2}/2 moles of
= 10.125