An aqueous solution contains
1 answer:
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Explanation:
The given data is as follows.
Width of Styrofoam = 24.0 cm
Length of Styrofoam = 36.0 cm
Height of Styrofoam = 5.0 cm
Therefore, volume of the Styrofoam will be calculated as follows.
Volume = length × width × height
= (36.0 × 24.0 × 5.0)
= 4320
or, =
As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.
So, volume of water displaced is as follows.
24.0 cm × 36.0 cm × 2.0 cm
=
Hence, mass of displaced water is as follows.
mass = density × volume
=
=
Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.
Mass of water displaced = mass of book + mass of Styrofoam
= 1500 g + mass of Styrofoam
(1730 - 1500) g = mass of Styrofoam
mass of Styrofoam = 230 g
Therefore, calculate the density of Styrofoam as follows.
Density =
=
=
Thus, we can conclude that the density of Styrofoam is .
Answer: -
12.41 g
Explanation: -
Mass of CO₂ = 42 g
Molar mass of CO₂ = 12 x 1 + 16 x 2 = 44 g / mol
Number of moles of CO₂ =
= 0.9545 mol
The balanced chemical equation for this process is
2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O
From the balanced chemical equation we see
12 mol of CO₂ is produced from 2 mol of C₆H₆
0.9545 mol of CO₂ is produced from
= 0.159 mol of C₆H₆
Molar mass of C₆H₆ = 12 x 6 + 1 x 6 =78 g /mol
Mass of C₆H₆ =Molar mass x Number of moles
= 78 g / mol x 0.159 mol
= 12.41 g