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Which of these substances are greenhouse gases? Check all that apply. Oxygen carbon dioxide helium methane nitrous oxide.

taurus [48]

The greenhouse gases are carbon dioxide, methane, and nitrous oxide.

The greenhouse effect has been defined as the entrapment of the sun's energy by the gases that result in the earth becoming warmer and a better place to live.

The gases present in the atmosphere that has been able to entrap the heat energy has been termed the greenhouse gases.

The greenhouse gases have been carbon dioxide, methane, and nitrous oxide.

For more information about greenhouse gases, refer to the link:

brainly.com/question/11595872

3 0

3 years ago

Balance this chemical equation Ca(OH)2 + HCl ---> CaCl2 + H2O

steposvetlana [31]

Answer:

The balance equation of Ca(OH)2 + HCl ---> CaCl2 + H2O

is

Ca(OH)2(s) + 2HCl(aq) ---> CaCl2(aq) +2H2O (l) (balanced equation)

6 0

3 years ago

Some fruits and vegetables are preserved by pickling them. Nandini got confused

stepan [7]

Answer:

ye

Explanation:

ye

3 0

3 years ago

Be sure to answer all parts. One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, whic

Sever21 [200]

Answer:

The annual production of carbon dioxide is $9.12\times 10^{10} kg$ .

Explanation:

Distance covered by each car = 5790 miles

Rate of consumption of gasoline =24. mile/gal

For every 24.1 mile 1 gallon of gasoline is used

Gasoline used by a single car by travelling 5790 miles =

$\frac{1}{24.1}\times 5790 mile=240.24 gal$

Number of cars in the United states = 40.0 million = $4\times 10^7$

Total gallons of gasoline consumed by 40 million cars = $4\times 10^7\times 240.24 gal=9.60\times 10^9 gal$

1 gallon of gasoline produces = 9.50 kg of $CO_2$

Then $9.60\times 10^9 gal$ of gasoline will produce:

$9.60\times 10^9\times 9.50 kg =9.12\times 10^{10} kg$ of $CO_2$

The annual production of carbon dioxide is $9.12\times 10^{10} kg$ .

6 0

3 years ago

How many grams of steam at 100 °C would be required to raise the temperature

Alex777 [14]

The mass of steam required to raise the temperature of water is 3.5 g.

The given parameters;

mass of the benzene, = 47.6
initial temperature of the benzene, = 5.5 ⁰C
final temperature of the benzene = 30 ⁰C

The molar mass of Benzene = 78.11 g/mol

The molar mass of water = 18 g/mol

The number of moles of the Benzene is calculated as follows;

$n = \frac{47.6}{78.11} = 0.61 \ mole$

The mass of steam required is calculated as follows;

heat lost by steam = heat absorbed by benzene

$\frac{m}{18} \times 40.7 \times 10^3 = 47.6(1.63)(30-5.5) \ + \ 0.61 \times 9.87 \times 10^3\\\\2261.11 m = 7921.61\\\\m = \frac{7921.61}{2261.11} \\\\m = 3.5 \ g$

Thus, the mass of steam required to raise the temperature of water is 3.5 g.

Learn more here:brainly.com/question/14963365

3 0

3 years ago