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Travka [436]
3 years ago
6

What is the theoretical yield of ammonia that can be obtained from the reaction of 10.0 g of H2 and excess N2?

Chemistry
1 answer:
julia-pushkina [17]3 years ago
8 0
I don’t know what to say about this question
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An impure sample of zinc (zn) is treated with an excess of sulfuric acid (h 2 so 4) to form zinc sulfate (znso4) and molecular h
daser333 [38]

a) The complete balanced chemical equation is:

 

Zn(s) + H2SO4(aq) --------> ZnSO4(aq) + H2 (g) 

<span>b) First we find the amount zinc that has reacted based on the given H2 produced.</span>

From stoichiometry 1 moles of Zn is needed for every 1 moles of H2 produced, therefore:

moles(Zn) = moles(H2) 

where moles is the ratio of mass and molar mass (MM)
mass(Zn) / MM(Zn) = mass(H2) / MM(H2) 
mass(Zn) = [mass(H2) / MM(H2)] * MM(Zn) 
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mass(Zn) = 2.49 g 

So we got 2.49 g pure zinc in the sample so the purity of zinc is therefore: 

purity = (2.49 / 3.86) * 100 % = 64.50 % 
 

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