37 is the right answer because 47 is not mutable and 27 is too short

**Benjamin** is **correct** about the **diameter **being** perpendicula**r to each other and the **points connected** around the **circle**.

<h3>

**Inscribing a square**</h3>

The steps involved in inscribing a square in a circle include;

- A diameter of the circle is drawn.

- A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.

- The resulting four points on the circle are the vertices of the inscribed square.

Alicia deductions were;

Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle

Benjamin's deductions;

The diameters must be perpendicular to each other. Then connect the points, in order, around the circle

Caleb's deduction;

No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.

It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.

Thus, **Benjamin** is **correct** about the **diameter **being** perpendicula**r to each other and the **points connected** around the **circle**.

Learn more about an **inscribed square** here:

brainly.com/question/2458205

#SPJ1

<h3>I'll teach you how to solve 20x^3+4x^2-45x-9</h3>

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20x^3+4x^2-45x-9

Add parentheses:

(20x^3+4x^2) + (-45x-9)

Factor out -9 and 4x^2:

-9(5x+1)+4x^2(5x+1)

Factor out the common term 5x+1:

(5x+1)(4x^2-9)

Factor 4x^2- 9:

(5x+1)(2x+3)(2x-3)

Your Answer Is **(5x+1)(2x+3)(2x-3)**

**plz mark me as brainliest :)**