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3 years ago

Which table represents a linear function

Mathematics

2 answers:

Ierofanga [76]3 years ago

6 0

Answer:

the first one

Step-by-step explanation:

its a table increasing by 5 for every 1 thing

like example

5 dollars for every 1 candy bar sold at a fundraiser

seraphim [82]3 years ago

3 0

The first table ...

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A circle is inscribed in an equilateral triangle. A point in the figure is selected at random. Find the probability that the poi

liubo4ka [24]

Answer:

The correct answer is first option 60%

Step-by-step explanation:

The radius of a circle is inscribed in an equilateral triangle with side a = a/2√3

To find the area of equilateral triangle

Here side be 'a'

Area of equilateral = √3a²/4

To find the area of circle

Here radius = a/2√3

Area = πr²

= π(a/2√3)

= 3.14a²/12

To find the probability

probability = area of circle/area of triangle

= 3.14a²/12/ √3a²/4

= 3.14/3√3

= 0.6043 ≈ 60.43 % 60 %

The correct answer is first option 60%

8 0

3 years ago

What is the sum of the arithmetic series 5 E(3n-2) N-1

vitfil [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

Write a story that could represent this math problem. A rectangle partitioned into thirds five times. The first part, the second

SSSSS [86.1K]

Answer:

The problem is 5 × 2/3 so

Billy paycheck every week was 2/3 a dollar which is approximately 66 cents but one day he did fantastic and got a raise and the raise was 5 times his last paycheck how much money is Billy new paycheck? So we do 5 × 2/3 and that equals 10/3, or 3 1/3, or 3 dollars and 30 cents.

Step-by-step explanation:

just copy and paste it.

7 0

3 years ago

Evaluate: (4x¹⁴)(8x¹¹) *

Marta_Voda [28]

Answer:

32x^25

Step-by-step explanation:

4x^14*8x^11

6 0

3 years ago

Accuracy in taking orders at a drive-through window is important for fast-food chains. Periodically, QSR Magazine publishes "The

pav-90 [236]

Answer:

a) 0.7412 = 74.12% probability that all the three orders will be filled correctly.

b) 0.0009 = 0.09% probability that none of the three will be filled correctly

c) 0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d) 0.9991 = 99.91% probability that at least one of the three will be filled correctly

e) 0.0082 = 0.82% probability that only your order will be filled correctly

Step-by-step explanation:

For each order, there are only two possible outcomes. Either it is filled correctly, or it is not. Orders are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The percentage of orders filled correctly at Burger King was approximately 90.5%.

This means that $p = 0.905$

You and 2 friends:

So 3 people in total, which means that $n = 3$

a. What is the probability that all the three orders will be filled correctly?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.905)^{3}.(0.095)^{0} = 0.7412$

0.7412 = 74.12% probability that all the three orders will be filled correctly.

b. What is the probability that none of the three will be filled correctly?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.905)^{0}.(0.095)^{3} = 0.0009$

0.0009 = 0.09% probability that none of the three will be filled correctly.

c. What is the probability that one of the three will be filled correctly?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.905)^{1}.(0.095)^{2} = 0.0245$

0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d. What is the probability that at least one of the three will be filled correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

With what we found in b:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0009 = 0.9991$

0.9991 = 99.91% probability that at least one of the three will be filled correctly.

e. What is the probability that only your order will be filled correctly?

Yours correctly with 90.5% probability, the other 2 wrong, each with 9.5% probability. So

$p = 0.905*0.095*0.095 = 0.0082$

0.0082 = 0.82% probability that only your order will be filled correctly

7 0

3 years ago