Answer:
d = 136.7 ft
Explanation:
Because the truck move with uniformly accelerated movement we apply the following formula:
vf²=v₀²+2*a*d Formula (1)
Where:
d:displacement in meters (ft)
v₀: initial speed in ft/s
vf: final speed in ft/s
a: acceleration in ft/s²
Data
v₀ = 44.0 mi/h
1milla = 5280 ft
1h = 3600 s
v₀ = 44*(5280 ft) / (3600 s) = 64.5 ft/s
vf = 0
d = 47.0 ft
Calculation of the acceleration of the truck
We replace data in the formula (1) :
vf²=v₀²+2*a*d
0 = (64.5)²+2*a*(47)
-(64.5)² = (94)*a
a = -(64.5)² / 94
a = - 44.26 ft/s²
The acceleration (a) it's negative (-) because the truck is braking
Calculation of the minimum stopping distance of the truck to v₀ = 75.0 mi/h
v₀ = 75 mi/h = 75* (5280 ft) / (3600s) = 110 ft/s
We replace v₀ = 110 ft/s and a = - 44.26 ft/s² in the formula (1):
vf²=v₀²+2*a*d
0 = (110)²+2*(-44.26)*d
88.52*d = (110)²
d = (110)² / (88.52)
d = 136.7 ft
Answer:
Explanation:
1.{1,3}2. adn as if bruh ma dude
Answer:
e is the answer
Force F=5.119*10^-4N
Explanation:
Given that
Current in wire a Ia=12A
Current in wire b (lb)=14A
Length of wire is L=6.4m
Distance apart (r)=42cm=0.42m
Also note that U°=4π*10^-7
We are to calculate for the force
F=(U°IaIbL/2πr)
F=4π*10^-7*12*14*6.4/2π*0.42)
F=5.119*10^-4N
"In nuclear reactions, mass is converted to energy" is the statement that <span>explains why more energy is released in nuclear reactions than in chemical reactions. The correct option among all the options that are given in the question is the last option or option "D". I hope the answer has come to your help.</span>
Answer:
1.6 meters east
Explanation:
Note: Image attached.
As we can see on the data, Anita is further from the puddle than Nick. Additionally, the distances relatives to the center of the puddle allow us to now the lenght of the rope which is the sum of these two, 9.2 meters. We also know that the knot is at the middle of the rope, so it means it is at 4.6 meters of both Anita and Nick. Now what is next? Well, we now have everything we know. We have the distance between Anita and the puddle and we also know the distance between Anita and the knot (4.6 meters). We just need to subtract the distance to the knot from the distance to the puddle which is equal to 1,6 meters east direction.
If you guys have any questions, just let me know.