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Ray Of Light [21]
3 years ago
14

Discuss the relationship between amperage, voltage, and power.

Physics
1 answer:
Stells [14]3 years ago
5 0

Electrical power, in watts  =  (voltage, in volts) x (current, in Amperes)
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A balloon filled with helium gas has an average density of rhob = 0.27 kg/m3. The density of the air is about rhoa = 1.23 kg/m3.
8_murik_8 [283]

Answer:34.84 m/s^2

   

Explanation:

Given

density of balloon \rho _{He}=0.27 kg/m^3

density of air \rho _a=1.23 kg/m^3

volume of balloon V=0.084 m^3

If balloon is rising then

F_b-mg=ma

where F_b=buoyant\ Force=\rho _a\times V\times g

mg=\rho _{He}\times V\times g=weight of gas

a=acceleration

\rho _a\times V\times g-\rho _{He}\times V\times g=\rho _{He}\times V\times a

\rho _a\times g-\rho _{He}\times g=\rho _{He}\times a

divide by \rho _{He}

\frac{\rho _a}{\rho _{He}}\times g-g=a

a=g(\frac{\rho _a}{\rho _{He}}-1)

a=g(\frac{1.23}{0.27}-1)

a=3.55\times 9.8

a=34.84 m/s^2

3 0
3 years ago
Which statement would be true about a water molecule if it has a linear shape
mihalych1998 [28]
It would be easily bond with other water molecules.
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Five liters of air at 50 c is warmed to 100c what is the new volume if the pressure remain constant
KonstantinChe [14]
To solve the problem, we can use Charle's law, which states that for an ideal gas at constant pressure the ratio between absolute temperature T and volume V remains constant:
\frac{T}{V}=k
For a gas transformation, this law can be rewritten as
\frac{T_1}{V_1}= \frac{T_2}{V_2} (1)
where 1 and 2 label the initial and final conditions of the gas.

Before applying the law, we must convert the temperatures in Kelvin:
T_1 = 50^{\circ}C + 273 = 323 K
T_2 = 100^{\circ}C+273=373 K
The initial volume of the gas is V_1 = 5 L, so if we re-arrange (1) we find the new volume of the gas:
V_2 = V_1  \frac{T_2}{T_1}=(5 L) \frac{373 K}{323 K}=5.77 L
8 0
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Explain the types of root​
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there are two main type of root systems.

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Good night all of you​
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Answer: Good night

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