Explanation:
Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 4.7 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (4.7 s) + ½ (9.8 m/s²) (4.7 s)²
Δy ≈ 110 m
Acceleration due to gravity will be constant, but the speed can change.
Answer:
770.1 m
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 45.3 m/s
Time (t) = 17 s
Displacement (d) =?
Velocity is defined according to the following formula:
Velocity = Displacement /Time
With the above formula, we can obtain the displacement of the ball as follow:
Velocity = Displacement /Time
45.3 = Displacement / 17
Cross multiply
Displacement = 45.3 × 17
Displacement = 770.1 m
Therefore the displacement of the ball is 770.1 m
600
mph
Velocity is the distance traveled in a given time, or
v
=
x
t
where
v
is velocity,
x
is distance and
t
is time.
Here,
x
=
3000
and
t
=
5.0
, so
v
=
x
t
=
3000
5
=
600
Don't forget units. Since the question's data is in miles and hours, the units will be miles per hour, or mph, so
3000
miles
5
hours
=
600
miles
hour
=
600
mph
