Anita and Nick are playing tug-of-war near a mud puddle. They are each holding on to an end of a taut rope that has a knot exact
ly in the middle. Anita's position is 6.2 meters east of the center of the puddle and Nick's position is 3.0 meters west of the center of the puddle. What is the location of the knot relative to the center of the puddle? Treat east as positive and west as negative.
1 answer:
Answer:
1.6 meters east
Explanation:
Note: Image attached.
As we can see on the data, Anita is further from the puddle than Nick. Additionally, the distances relatives to the center of the puddle allow us to now the lenght of the rope which is the sum of these two, 9.2 meters. We also know that the knot is at the middle of the rope, so it means it is at 4.6 meters of both Anita and Nick. Now what is next? Well, we now have everything we know. We have the distance between Anita and the puddle and we also know the distance between Anita and the knot (4.6 meters). We just need to subtract the distance to the knot from the distance to the puddle which is equal to 1,6 meters east direction.
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Answer: magnitude of applied force is FA = mg + F
Where F is the resultant force downward that the rope moves with
Explanation:
Force downwards F is,
F = FA - T
T is the upwards tension force on the rope
FA is the actual applied force in pulling the rope down.
Therefore, T = FA - F .....equ. (1)
For the box to move up with force ma ( it's mass times its acceleration upwards) upwards tension on the roap must exceed its own weight mg ( it's mass times acceleration due to gravity 9.8m/s^2)
Therefore, ma = T - mg
T = ma + mg ..... equ. (2)
Equating equ. 1 and 2
T = FA - F = ma + mg
Therefore FA = ma + mg + F
But at constant velocity a = 0
Magnitude of applied force becomes
FA = mg + F
See image below
