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Answer:
19.3m/s
Explanation:
Use third equation of motion

where v is the velocity at halfway, u is the initial velocity, g is gravity (9.81m/s^2) and h is the height at which you'd want to find the velocity
insert values to get answer
![v^2-0^2=2(9.81m/s^2)(38/2)\\v^2=9.81m/s^2 *38\\v^2=372.78\\v=\sqrt[]{372.78} \\v=19.3m/s](https://tex.z-dn.net/?f=v%5E2-0%5E2%3D2%289.81m%2Fs%5E2%29%2838%2F2%29%5C%5Cv%5E2%3D9.81m%2Fs%5E2%20%2A38%5C%5Cv%5E2%3D372.78%5C%5Cv%3D%5Csqrt%5B%5D%7B372.78%7D%20%5C%5Cv%3D19.3m%2Fs)
Answer:
longitudinal and transverse.
Explanation:
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Speed of particle B is 2v₀/3 m/s to the left. Particle A and particle B will always have equal speed since they experience equal forces.
<h3>Conservation of energy</h3>
The speed and direction of the particle B is determined by applying the principle of conservation of energy as follows;
K.E₁ + P.E₁ = K.E₂ + P.E₂


At any given position, the speed of particle A and particle B will be equal, since they experience equal force and they have equal masses.
The complete question is below:
Particle A and particle B, each of mass M, move along the x-axis exerting a force on each other. The potential energy of the system of two particles assosicated with the force is given by the equation U=G/r 2, where r is the distance between the two particles and G is a positive constant. At time t=T1 particle A is observed to be traveling with speed 2vo/3 to the left. The speed and direction of motion of particle B is ?
Learn more about conservation of energy here: brainly.com/question/166559
The approximate speed of the sound wave traveling through the solid material is 1012m/s.
<h3>
Wavelength, Frequency and Speed</h3>
Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
From the wavelength, frequency and speed relation,
λ = v ÷ f
Where λ is wavelength, v is velocity/speed and f is frequency.
Given the data in the question;
- Frequency of sound wave f = 440Hz = 440s⁻¹
- Wavelength of the wave λ = 2.3m
To determine the approximate speed of the wave, we substitute our given values into the expression above.
λ = v ÷ f
2.3m = v ÷ 440s⁻¹
v = 2.3m × 440s⁻¹
v = 1012ms⁻¹
v = 1012m/s
Therefore, the approximate speed of the sound wave traveling through the solid material is 1012m/s.
Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701