Question

Third fifth and seventeenth terms of of the sequence f(n)=3+n-1/2=

Answer 1

Answer:

$f(3) = \frac{11}{2}$

$f(5) = \frac{15}{2}$

$f(17) =\frac{39}{2}$

Step-by-step explanation:

Given

$f(n) = 3 + n - \frac{1}{2}$

Solving (a): The 3rd term

This implies that n = 3

So:

$f(3) = 3 + 3 - \frac{1}{2}$

Take LCM

$f(3) = \frac{6 + 6 -1}{2}$

$f(3) = \frac{11}{2}$

Solving (b): The 5th term

This implies that n = 5.

So:

$f(5) = 3 + 5 - \frac{1}{2}$

Take LCM

$f(5) = \frac{6 + 10 - 1}{2}$

$f(5) = \frac{15}{2}$

Solving (c): The 17th term

This implies that n = 17

So:

$f(17) = 3 + 17 - \frac{1}{2}$

Take LCM

$f(17) =\frac{6 + 34 - 1}{2}$

$f(17) =\frac{39}{2}$