This dilution problem uses the equation M a V a = M b V b
M a = 6.77M - the initial molarity (concentration) V a = 15.00 mL - the initial volume M b = 1.50 M - the desired molarity (concentration) V b = (15.00 + x mL) - the volume of the desired solution (6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x ) 101.55 M mL= 22.5 M mL + 1.50x M 101.55 M mL - 22.5 M mL = 1.50x M 79.05 M mL = 1.50 M 79.05 M mL / 1.50 M = x 52.7 mL = x 59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M. I hope this was helpful.
N = (PV)/RT (T = 88.78 + 273 = 361.78K) (R = 22.4/273 = 0.082) = (5.49 x 22.03)/(0.082 x 361.78) = ? Put it into the calculator. It's hard to do that on a mobile phone.