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Sav [38]
3 years ago
8

If I have a molar concentration of Na2S2O3 of .02M and a volume of .001L. As well as a Molar Concentration of KI .3M and H2O2 of

.1M. The equation of the reaction is 2S2O3+I3 ->3I+S4O6. The question is "How many moles of S2O3 are consumed". Do I just use the Molar concentration and the volume of the Na2S2O3?
Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
4 0
You have to use everything that is given since you have to know which is the limiting reactant. We find the limiting reactant by calculating the number of moles of each reactant and compare the number of moles. The limiting reactant would be the one that is consumed fully by the reaction.


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Write empirical formula
andrew11 [14]

Answer:

Pb(ClO_{3})_{4}\\Pb(MnO_{4})_{4}\\Fe(ClO_{3})_{3}\\\Fe(MnO_{4})_{3}\\

Explanation:

Pb^{4+}(ClO_{3}^{-})_{4}--->Pb(ClO_{3})_{4}\\Pb^{4+}(MnO_{4}^{-})_{4}--->Pb(MnO_{4})_{4}\\Fe^{3+}(ClO_{3}^{-})_{3}--->Fe(ClO_{3})_{3}\\\Fe^{3+}(MnO_{4}^{-})_{3}--->Fe(MnO_{4})_{3}\\

3 0
3 years ago
Consider separate solutions of NaOH and KClmade by dissolving 100.0 g of each solute in 250.0 mL of solution. Calculate the conc
gladu [14]

Answer:

Explanation:

MW of NaOH = 40 g/mol

MW of KCl = 74.55 g/mp;

250 mL = .25 L

100g NaOH / 40 g = 25 mol

100g KCl/ 74.55g = 1.34 mol

Molarity of NaOH: 25/.25 = 100M

Molarity of KCl: 1.34/.25 = 5.36 M

8 0
2 years ago
What is the pH of a 0.08 M solution of Ca(OH),?
torisob [31]

Answer:

pH = 12.20

Explanation:

Ca(OH)2 is a strong base, so it dissociates completely. A 0.08 M solution of Ca(OH)2 is 0.16 M OH-, since every mole of Ca(OH)2 has 2 OH-.

Calculate pOH using [OH-] = 0.16 M

pOH = -log(0.16) = 0.80

pH = 14 - pOH = 14 - 0.80 = 12.20

4 0
3 years ago
If 1.9 kJ of heat is transferred to 96 g aluminum at 113°C, what would the
erastova [34]

Answer:

T2 = 135.1°C

Explanation:

Given data:

Mass of water = 96 g

Initial temperature = 113°C

Final temperature = ?

Amount of energy transfer = 1.9 Kj (1.9×1000 = 1900 j)

Specific heat capacity of aluminium = 0.897 j/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Now we will put the values in formula.

Q = m.c. ΔT

1900 j = 96 g × 0.897 j/g.°C × T2 - 113°C

1900 j = 86.112 j/°C × T2 - 113°C

1900 j / 86.112 j/°C = T2 - 113°C

22.1°C + 113°C =  T2

T2 = 135.1°C

4 0
3 years ago
15 POINTS!!!!!!
pickupchik [31]
He proposed the Law of Conservation of Matter, being the first to say that matter can not be created nor destroyed.
4 0
3 years ago
Read 2 more answers
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