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Sav [38]
3 years ago
8

If I have a molar concentration of Na2S2O3 of .02M and a volume of .001L. As well as a Molar Concentration of KI .3M and H2O2 of

.1M. The equation of the reaction is 2S2O3+I3 ->3I+S4O6. The question is "How many moles of S2O3 are consumed". Do I just use the Molar concentration and the volume of the Na2S2O3?
Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
4 0
You have to use everything that is given since you have to know which is the limiting reactant. We find the limiting reactant by calculating the number of moles of each reactant and compare the number of moles. The limiting reactant would be the one that is consumed fully by the reaction.


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Two substances, A and Z, are to be identified. Substance A can not be broken down by a chemical change. Substance Z can be broke
I am Lyosha [343]
The answer is 3). This is because elements are the simplest form of a substance, and cannot be broken down any further. Compounds on the other hand are much more complex than elements and can be broken down INTO elements. For example, Na, sodium, is an element and cannot be broken down further. H2O, water, is a compound and can be broken down into Hydrogen and Oxygen.
4 0
3 years ago
Perform the following mathematical operation and express the results to the correct number of significant figures. (0.102 x 0.08
Kobotan [32]

Answer:

<u>2.26 </u>

<u></u>

Explanation:

First you should know what are significant figures,

1 . All non - zero digits are significant.

2 . The zero between two non-  zero are significant.Ex 302 has 3 significant figures.

3. The zero before the decimal and before any non-zero digit is non significant. Example : 0.003 has only 1 significant figure.

4. The zero after non zero are non - significant . But the zeros after the decimal point are significant.

300 has only 1 significant figure

300.0 has 4 significant figure

The least number of significant figures present in the number should be there in the final answer of the calculation.

Look at the number having minimum significant digits :

It is 3 (every number has 3- significant figures ) So the answer should also contain 3 - significant figures.

\frac{0.102\times 0.0821\times 273}{1.01}

First solve the numerator part

\frac{2.285}{1.01}

=2.2635

Round off this number to 3 significant figures.

Answer is =<u> 2.26</u>

It has 3 - significant digit since all the digits are non-zero.

5 0
3 years ago
The reaction of HCl with NaOH is represented by the equation HCl( aq) + NaOH( aq) ® NaCl( aq) + H 2O( l) What volume of 0.631 M
Darina [25.2K]

8.04 mL.

<h3>Explanation</h3>

How many moles of NaOH?

Note the unit:

V = 15.8 \; \textbf{mL} = \dfrac{15.8}{1000}\;\textbf{L} = 0.0158 \; \text{L}.

n = c\cdot V = 0.0158 \times0.321 = 0.00507\;\text{mol}.

How many moles of HCl?

As seen in the equation, HCl and NaOH reacts at a 1:1 ratio.

n(\text{HCl}) = n(\text{NaOH}) = 0.00507\;\text{mol}.

How many mL of HCl?

V = \dfrac{n}{c} =\dfrac{0.00507}{0.631} = 0.00804\;\text{L} = 0.00804\times 1000 \;\textbf{mL} = 8.04\;\text{mL}.

5 0
3 years ago
Question 11 : Why was Newlands law of octaves rejected?____________
KatRina [158]
It could not hold good for elements heaver than calcium.
7 0
3 years ago
How many mg of salt are in a 2.78 kg bag of salt?
igomit [66]

Answer:

2,780,000mg

Explanation:

Using the Metric Staircase photo provided, you can calculate how many mg there are in 2.78 kg by simply moving the decimal point six places to the right, since the "Kilo" step takes six places to move to the "Milli" step.

2.78 kg

---------------

2 7 8 0 0 0 0 .

we can see that the decimal point is moved to the right six places.

Answer:

2,780,000mg

7 0
3 years ago
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