<span>First we need to find the energy of one photon with a wavelength of 589 nm.
E = hc / wavelength
E = (6.63 x 10^{-34} J s)(3 x 10^8 m/s) / (589 x 10^{-9} m)
E = 3.3769 x 10^{-19} Joules
To find N, the number of photons, we need to divide the total energy by the energy of each photon.
N = 623000 J / 3.3769 x 10^{-19} Joules
N = 1.84 x 10^{24} photons
There are 1.84 x 10^{24} photons in the burst of yellow light.</span>
Answer:
Energy lost is 7.63×10⁻²⁰J
Explanation:
Hello,
I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5
E = hc/λ(1/n₂² - 1/n₁²)
n₁ = 15
n₂ = 5
hc/λ = 2.18×10⁻¹⁸J (according to the data)
E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)
E = 2.18×10⁻¹⁸ (1/15² - 1/5²)
E = 2.18×10⁻¹⁸ ×(-0.035)
E = -7.63×10⁻²⁰J
The energy lost is 7.63×10⁻²⁰J
Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level
The wind vane, the rain gauge, the anemometer, the barometer, and the thermometer.
The reaction is an equilibrium represented by the equation
<span>Ag2CO3(s) + 2 HNO3(aq) <----> 2 AgNO3(aq) + H2O(l) + CO2(g) </span>
From the <span>Le Chatelier's Principle which </span>states that changing a factor such as concentration, temperature, or pressure of a reaction at equilibrium will cause the reaction to shift in the direction that counteracts the effect of that change.
Therefore; the CO2 produced starts escaping and the concentration and pressure of CO2 drops. The system responds by trying to increase the concentration and pressure of CO2 by producing more. This means more and more Ag2CO3 will dissolve due to reaction with the acid, HNO3.
This continues until one of the reactants is exhausted.
Answer:
Liquids and gases flow easily because their particles can move or slide past one another.
Explanation:
Hope this helped Mark BRAINLEST!!
