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erica [24]
3 years ago
9

Answer please????? Thank you

Chemistry
1 answer:
snow_tiger [21]3 years ago
7 0
Can’t have anything in Detroit
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Calculate the standard enthalpy change of formation of CHA given that the standard enthalpies change of combustion of methane, g
Nostrana [21]

Answer : The standard enthalpy of formation of methane is, -74.8 kJ/mole

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of CH_4 will be,

C(s)+2H_2(g)\rightarrow CH_4(g)    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l)     \Delta H_1=-890kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.4kJ/mole

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-285.7kJ/mole

Now we will reverse the reaction 1, multiply reaction 3 by 2 then adding all the equations, we get :

(1) CO_2(g)+2H_2O(l)\rightarrow CH_4(g)+2O_2(g)     \Delta H_1=890kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.4kJ/mole

(3) 2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=2\times (-285.7kJ)=-571.4kJ/mole

The expression for enthalpy of formation of CH_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+890kJ/mole)+(-393.4kJ/mole)+(-571.4kJ/mole)

\Delta H=-74.8kJ/mole

Therefore, the standard enthalpy of formation of methane is, -74.8 kJ/mole

3 0
3 years ago
What is the atomic mass of an element that has 37 protons, 43 neutrons, and 36 electrons?
Veronika [31]

Answer:

the atomic mass of the element with 37 protons,43 neutrons and 36 electrons is 80

3 0
3 years ago
3 Ag2S + 2 Al + 3 H2O --> 6 Ag + Al2O3 + 3 H2S
USPshnik [31]

Answer: really hard

Explanation: I wish I knew how to help you

3 0
3 years ago
Name two metals that do not always lose the same number of electrons
Natalija [7]
It would be copper and iron -A
4 0
3 years ago
Read 2 more answers
Which two physical properties allow a mixture to be separated by chromatography
Slav-nsk [51]

Answer:


                 Option-1 (Solubility and Molecular polarity) is the correct answer.


Explanation:


                        Thin Layer Chromatography is employed to separate a mixture of non volatile compounds. In this technique an adsorbent material like silica gel is coated on a plastic, glass or aluminium sheet. Then the mixture of compounds is applied at the bottom of sheet and the sheet is placed in the container containing a solvent system. It is observed that the solvent starts travelling upward through capillary action.


While the solvent is running the mixture of compounds starts separating from each other. This separation is due to following physical properties.


1) Solubility of Mixture in Solvent:

                                                          In a mixture those compounds which has more solubility in solvent will travel more and will give greater Rf value and the less soluble will left behind with smaller Rf value. Hence due to solubility a mixture of compounds can be separated.


2) Polarity of Molecules:

                                          As the stationary phase (adsorbent material) is polar in nature, so in mixture those compounds which are less polar will less interact with the stationary phase and will travel more with greater Rf value, while, more polar molecules will form stronger interactions with the stationary phase, hence will travel less and therefore, will show smaller Rf values.


6 0
3 years ago
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