Answer:
B. y = 4x
Step-by-step explanation:
** 4 blocks = 1 unit [vertically]
Starting from the origin, you do <em>rise</em><em>\</em><em>run</em><em> </em>by moving four blocks <em>north</em><em> </em>over one block <em>east</em><em>.</em><em> </em>This graph is an example of what is known as direct variation.
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Answer:
Negative
Step-by-step explanation:
From the scatter plot displayed, we could clearly observe the direction of the trend line as it produces a negative slope. For high values of y, the values of x are low and similarly, high values of x have low y values. Therefore, this kind of relationship between the two variables is considered negative.
For a relation to be called a function, it must pas the vertical line test and each x-value must have a unique y-value
<span>The graph of this sequence would pass the vertical line test.
</span>Each day corresponds to a unique amount of pennies in this sequence.


Cancel out the denominators.
(x+5)² + 18 = -30
(x+5)² = -30 - 18
(x+5)² = -48
The equation is impossible, we have a negative number.
There isn't a number that squared gives a negative number (the square is always positive).
√(x+5)² = +/- √-48
x+5 = +/- √-48
IMPOSSIBLE
You can write the result in imaginary numbers
x+5=+/- 4i√3
By decomposing the figure in simpler shapes, we will see that the total area is:
a = 180 cm²
<h3>
How to find the area of the composite figure?</h3>
Remember that the area of a rectangle of width W and length L is:
A = L*W
And the area of a triangle with base B and height H is:
A = B*H/2.
Then, the upper part can be seen as a rectangle of length of 6cm and width of 6 cm, with two triangles on the sides, such that each triangle has a base of 3cm and a height of 6cm.
So the area of that part is:
A = 6cm*6cm + 2*(3cm*6cm/2) = 54cm²
Now, the bottom triangle has a base of 12 cm, and a height of:
15cm - 6cm = 9cm
Then its area is:
A' = 12cm*9cm/2 = 54cm²
This means that the total area of the figure is:
total area = 54cm² + 54cm² = 108cm²
If you want to learn more about area:
brainly.com/question/24487155
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