The combination shows that the different groups of three that can be chosen for a newspaper photo is 10.
<h3>How to calculate the value?</h3>
From the information, Joyce, Karen and Paula are starters on their school basketball team.
The information is to illustrate the different groups of three that can be chosen for a newspaper photo.
This will be:
= 5!/3!(5 - 3)!
= 5!/3!2!
= (5 × 4 × 3 × 2 × 1)/(3 × 2 × 2)
= 20/2
= 10
There will be 10 groups.
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Answer:
For the problem we have:
Sam had 14 people at the party.
The party lasted for 4 hours.
He paid $2 for each person's skate rental and 3 for each person's entry ticket.
Suppose we want to know how much Sam spent on the party.
But we do not know if the $2 of the skate rental are per hour or per two hours, or in total, for example, if the amount is per hour, then the total amount for each skate is $2*4 = $8, so in the case that the rental depends on the time, we can not solve this problem because we do not have enough information.
If the $2 are fixed (do not depend on the time that the party lasted) then the fact that the party lasted for 4 hours does not matter.
We can calculate as 14 persons* ($2 + $3) each = 14*$5 = $70, then you can see that in this case the 4 hours data is not necessary
Answer:
i think the answer is -3/4
Answer:
C is the correct answe i need brainliest
2x2 + x −#6 _____________
x2 − 1
∙ x
__
2 + 2x + 1
x 2 − 4
Rewrite as multiplication.
(2x − 3)(x + 2) __
(x + 1)(x − 1) ∙ (x + 1)(x + 1) __ (x + 2)(x − 2) Factor the numerator and denominator.
(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Multiply numerators and denominators.
(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Cancel common factors to simplify.
(2x − 3)(x + 1) __ (x − 1)(x − 2)
