Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0
Hi, did you attach the picture for it?
The dollar amount of the flotation costs by percent of gross proceeds is $5,000
We need to know about the percent theory first, percent is per 100. So when A is 1% of B it means that
A = 1/100 x B
From the question, we know that
The gross proceeds is given by = $250,000 and
the flotation cost is given by = 2% of gross proceeds.
We can write the flotation cost as
Flotation cost = 2/100 x $250,000
Flotation cost = 2/100 x $250,000
Flotation cost = $5,000
Hence, the dollar amount of the flotation costs is $5,000
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Answer:
option-D
Step-by-step explanation:
we are given
Let's assume it is equal to 0
We can use quadratic formula
Suppose, we are given quadratic equations as
we can compare and find a,b and c
a=1 , b=2 , c=4
now, we can plug values
and we get
now, we can simplify it
and we get
Answer:
y = 2x + 5
Step-by-step explanation:
thats your graph: tell me of somethings wrong with the picture or you need anything else
