Item 9 Evaluate (3−1) 3 +7(6)− 5 2 (3−1)3+7(6)−52 .

BRAINLIEST! BRAINLIEST! PERMUTATION Find the value: (show your solution)

dlinn [17]

Answer:

$(1) \ _8P_8 = 40320\\\\(2) \ _1_0P_4 = 5040\\\\(3) \ \frac{_1_0P_5}{_5P_3} = 504\\\\(4) \ \frac{_6P_2 \ . \ _8P_5}{_1_0P_6} = 1\frac{1}{3} \\\\(5) \ \frac{_8P_2 \ . \ _8P_6}{_7P_6 \ . \ _4P_2} = 18\frac{2}{3}$

Step-by-step explanation:

$(1) \ _8P_8 = \frac{8!}{(8-8)!} = \frac{8!}{0!} = 8! = 40320$

$(2) \ _1_0P_4 = \frac{10!}{(10-4)!} = \frac{10!}{6!} = \frac{10\times 9\times 8 \times 7 \times 6!}{6!} = 10\times 9\times 8 \times 7 = 5040$

$(3) \ \frac{_1_0P_5}{_5P_3} =\frac{(10!)/(10-5)!}{(5!)/(5-3)!} = \frac{(10!)/(5!)}{(5!)/(2!)} = \frac{10\times 9 \times 8\times 7\times 6}{5\times 4 \times 3} = 504$

$(4) \ \frac{_6P_2 \ . \ _8P_5}{_1_0P_6} = \frac{(6!)/(6-2)! \ \times\ (8!)/(8-5)!}{(10!)/(10-6)!} = \frac{(6!)/(4!) \ \times \ (8!)/(3!)}{(10!) /(4!)} = \frac{6! \ \times \ 8!}{10! \ \times \ 3!} \\\\= \frac{6\times 5 \times 4 \times 3! \ \times 8!}{10\times 9 \times 8! \ \times \ 3!} = \frac{6\times 5 \times 4}{10\times 9} = \frac{4}{3} = 1\frac{1}{3}$

$(5) \ \frac{_8P_2 \ . \ _8P_6}{_7P_6 \ . \ _4P_2} = \frac{(8!)/(6!) \ \times \ (8!)/(2!)}{(7!)/(1!) \ \times \ (4!)/(2!)} = \frac{8! \ \times \ 8!}{7! \ \times \ 6! \ \times \ 4!} = \frac{(8 )\ \times \ (8 \times 7)}{4!} =\frac{(8 )\ \times \ (8 \times 7)}{4\times 3 \times 2}\\\\= \frac{56}{3} = 18 \frac{2}{3}$

3 0

3 years ago

Express the ratio below in its simplest form. 3 1 2 : 4.5

cupoosta [38]

Answer:

69.3

Step-by-step explanation:

Divide both sides by 4.5

312/4.5 : 4.5/4.5

69.3 : 1

8 0

4 years ago

If - 6x +11 = 29 then 5x = ?

weeeeeb [17]

Answer:

5x= -15 I think

Step-by-step explanation:

You would have to solve the -6x+11=29 to find the value of x. To do so you would subtract the 11 from both sides leaving you with -6x=18. Then you divide that by -6 to find x. So x=-3. To find what 5x equals you would just plug in -3 as x and multiply 5(-3). Leaving you with -15.

5 0

3 years ago

Name the subset of the real number to which each number belongs 1. square root of 11 2. -7

Ganezh [65]

1 and 2 are natural numbers
-7 belongs to set of integers
sqrt 11 is a member of the set of irrational numbers

6 0

3 years ago

PPPLLLEEEAAASSSEEEE help ASAP! third time i have tried i need an answer right now!

Katarina [22]

Answer:

$x=2($ $\sqrt{6} -1)$ , $x= -2(1+\sqrt{6} )$