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3 years ago

Plz help me!!!!!i need to get this correct plz help!!!

Mathematics

1 answer:

____ [38]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

Yes they are because if you divide 18 by 3 you get six and if you divide 15 by 3 you get 5, so it simplifies to 6:3 which is the same as the ratio for rings

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She has driven for about 1 hour and 28 minutes

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3 years ago

Ten times the sum of half a number and 6 is 8

Digiron [165]

Answer:

I think it's 7

Step-by-step explanation:

I'm guessing I think

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3 years ago

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1 ball of wool is 125m, how many balls are there with 604m??

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Answer:

4.8 balls of wool

Step-by-step explanation:

604÷125=4.8

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2 years ago

HELP PLEASE!!! 10 PTS!!

allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD (Given)

$\angle ADC\cong \angle ACD$

$m\angle ADC=m\angle ACD$

According to the angle sum property, the sum of interior angles of a triangle is 180°.

$m\angle ADC+m\angle ACD+m\angle DAC=180$

$m\angle ACD+m\angle ACD+44=180$

$2m\angle ACD=180-44$

$2m\angle ACD=136$

Divide both sides by 2.

$m\angle ACD=68$

CE bisects ∠ACD.

$m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}$

$m\angle ACE=m\angle DCE=\dfrac{68}{2}$

$m\angle ACE=m\angle DCE=34$

Use angle sum property in triangle CDE,

$m\angle CDE+m\angle DCE+m\angle DEC=180$

$68+34+m\angle DEC=180$

$102+m\angle DEC=180$

Subtract 102 from both sides.

$m\angle DEC=180-102$

$m\angle DEC=78$

Therefore, the measure of angle DEC is 78°.

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2 years ago

Is the following statement always, sometimes, or never true? “The supplement of an acute angle is an obtuse angle.” Explain your

balu736 [363]

Answer:

Always

Step-by-step explanation:

An acute angle is an angle that is less than 90. Supplementary angles add up to 180.

So 180-89= 91

An obtuse angle is any angle that is greater than 90.

Here's a link to a better explanation.

brainly.com/question/14180317

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2 years ago

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