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2 years ago

In ATUV, the measure of V=90°, TU = 24 feet, and VT = 15 feet. Find the measure

Mathematics

1 answer:

olchik [2.2K]2 years ago

8 0

Answer:39

Step-by-step explanation: yes

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Determine if the equation 2x=y represents a proportional relationship.

Romashka-Z-Leto [24]

Answer:

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Proportional Relationships

A proportional relationship is one in which two quantities vary directly with each other. We say the variable y varies directly as x if:

y=kx

for some constant k , called the constant of proportionality .

(Some textbooks describe a proportional relationship by saying that " y varies proportionally with x " or that " y is directly proportional to x .")

This means that as x increases, y increases and as x decreases, y decreases-and that the ratio between them always stays the same.

The graph of the proportional relationship equation is a straight line through the origin.

5 0

2 years ago

At a local high school football game, twice the number of students attended as adults. If student tickets were $6.50, adult tick

lesantik [10]

Answer:

454

Step-by-step explanation:

set up a system of equation

let y be the number of students

let x be the number of adults

because there are twice the amount of students attended as adults, we can use y=2x as one equation

the other equation will be 6.5y+9x=4972 because this represents the total amount of money

plug 2x for y : 6.5(2x)+9x=4972 : x=226

plug 226 in for the first equation : y=2(226) : y=452

8 0

3 years ago

If sin A = 3/8, find the value of cosec A - sec A.

alexira [117]

Answer:

$\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

Step by step explanation:

$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

$\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}$

$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

6 0

2 years ago

How do you solve (3*x) *7

shtirl [24]

$3\cdot x\cdot7=21x$

6 0

3 years ago

I will give Brainliest!

Grace [21]

Answer:

2.9 years

Step-by-step explanation:

4 0

2 years ago