<span>What is the y-intercept of the plane whose equation is 4x + 5y + z = 20?
(0, 4, 0)
Which equation has intercepts at X(1, 0, 0), Y(0, 1, 0), and Z(0, 0, 2)?
2x + 2y + z = 2
Which equation is equivalent to x + 3y + z = 3?
4x + 12y + 4z = 12
Which of the following points lies in the plane 3x + 2y + 4z = 12?
(4, 3,2)
Hope these answer the questions. Have a nice day.</span>
Answer:
Note that orthogonal to the plane means perpendicular to the plane.
Step-by-step explanation:
-1x+3y-3z=1 can also be written as -1x+3y-3z=0
The direction vector of the plane -1x+3y-3z-1=0 is (-1,3,-3).
Let us find a point on this line for which the vector from this point to (0,0,5) is perpendicular to the given line. The point is x-0,y-0 and z-0 respectively
Therefore, the vector equation is given as:
-1(x-0) + 3(y-0) + -3(z-5) = 0
-x + 3y + (-3z+15) = 0
-x + 3y -3z + 15 = 0
Multiply through by - to get a positive x coordinate to give
x - 3y + 3z - 15 = 0
Answer:
if sin (x-3) degrees = cos (2x+6) degrees, find the value of x.
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Note: sin and cos are complementary functions....
sin(x) = cos (90-x)
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Your Problem:
sin(x-3) = cos(90-(x-3))
Equation:
90-[x-3] = 2x+6
90-x+3 = 2x+6
3x = 93-6
x = 31-2
x = 29
Step-by-step explanation:
Answer:
y= -69/8 (negative 69 over 8)
Step-by-step explanation:
First, you have to simplify both sides of the equation:
Second, add 3/4 to both sides:
-2/3y +-3/4 + 3/4=5 +3/4
-2/3y= 23/4
Next, multiply both sides by 3/(-2) (3 over -2)
(3/-2)*(-2/3y)= (3/-2) * (23/4)
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<em><u>y= -69/8</u></em>
Answer:
The Answer is D
Step-by-step explanation:
