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Sphinxa [80]
2 years ago
14

Please help me out ASAP!!!!!!!!

Mathematics
1 answer:
olga55 [171]2 years ago
6 0

Answer:

It is because the red disks were more than the other disks before the pupils added other disks.

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a metal strip is being installed around a workbench that is 6 feet long and 2 feet wide. find how much stripping is needed
Stolb23 [73]
Given that the metal strip is being installed around a bench that 6ft long 2ft wide. The metal required will be given by:
P=4(L+W)
=4(6+2)
=4(8)
=32 ft
Therefore we conclude that we need a metal strip that is 32ft long
4 0
3 years ago
If you travel 550 miles in 8 hours, what is your unit rate?​
Rama09 [41]

Answer:

68.785 miles per hour

Step-by-step explanation:

make one of the numbers 0 and divide the other one by that number

8 0
2 years ago
Read 2 more answers
Please HELP ME ON THIS MATH WRITTEN RESPONSE QUESTION.. THANK YOU
sergij07 [2.7K]

Answer:

Quadrilateral ABCD is not a square. The product of slopes of its diagonals is not -1.

Step-by-step explanation:

Point A is (-4,6)

Point B is (-12,-12)

Point C is (6,-18)

Point D is (13,-1)

Given that the diagonals of a square are perpendicular to each other;

We know that the product of slopes of two perpendicular lines is -1.

So, slope(m) of AC × slope(m) of BD should be equal to -1.

Slope of AC = (Change in y-axis) ÷ (Change in x-axis) = (-18 - 6) ÷ (6 - -4) = -24/10 = -2.4

Slope of BD = (Change in y-axis) ÷ (Change in x-axis) = (-1 - -12) ÷ (13 - -12) = 11/25 = 0.44

The product of slope of AC and slope of BD = -2.4 × 0.44 = -1.056

Since the product of slope of AC and slope of BD is not -1 hence AC is not perpendicular to BD thus quadrilateral ABCD is not a square.

4 0
3 years ago
Can someone help me please
denpristay [2]

Area of rhombus = length x height = 6 x 4 = 24 units²



Answer: 24 units²

4 0
3 years ago
Consider the equation below.
Korvikt [17]

Answer:

Equation in square form:

y=3(x+5)^2-4

Extreme value:

(h,k)=(-5,-4)

Step-by-step explanation:

We are given

y=3x^2+30x+71

we can complete square

y=3(x^2+10x)+71

we can use formula

a^2+2ab+b^2=(a+b)^2

y=3(x^2+2\times x\times 5)+71

now, we can add and subtract 5^2

y=3(x^2+2\times x\times 5+5^2-5^2)+71

y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71

y=3(x+5)^2-75+71

So, we get equation as

y=3(x+5)^2-4

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

y=a(x-h)^2+k

where

vertex=(h,k)

now, we can compare and find h and k

y=3(x+5)^2-4

we get

h=-5

k=-4

so, extreme value of this equation is

(h,k)=(-5,-4)

6 0
3 years ago
Read 2 more answers
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