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Kay [80]
3 years ago
6

5. A flock of geese flies 50 miles per hour. Write a linear

Mathematics
2 answers:
MrMuchimi3 years ago
7 0

Answer:

y=50x+0

Step-by-step explanation:

y=mx+b is y-intercept form

I will make x= hours and y= distance (miles)

every 1 you add to x has to represent 50 miles

for the y intercept, it was unspecified so I assumed 0

Hope this helps :)

Sonja [21]3 years ago
5 0

Answer:

y=50x

Step-by-step explanation:

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3 years ago
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Friends needs this anwsered help
olya-2409 [2.1K]

Answer:

  3, 8, 14, 30, 58

Step-by-step explanation:

As with all formulas, put the numbers in place of the corresponding variables, and do the arithmetic.

  a_1=3\qquad\text{given}\\\\a_2=8\qquad\text{given}\\\\a_3=2a_1+a_2=2(3)+8=14\\\\a_4=2a_2+a_3=2(8)+14=30\\\\a_5=2a_3+a_4=2(14)+30=58

The first 5 terms of the sequence are 3, 8, 14, 30, 58.

4 0
2 years ago
Five snails are having a race. The snail's speeds are given in the table. Which two snails are going the same rate of speed?
kobusy [5.1K]

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2 1/5 for alice

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4 0
3 years ago
What is the simplified form of √144x^36
Nadusha1986 [10]

Answer:

The simplified form of \sqrt{144x^{36}} is 12x^{18}

Step-by-step explanation:

Given : \sqrt{144x^{36}}

We have to write the simplified form of \sqrt{144x^{36}}

Consider the given expression \sqrt{144x^{36}}

We know \sqrt{144}=12

and \sqrt{x^{36}}=\sqrt{x^{18}\cdot x^{18}}

Thus,

\sqrt{144x^{36}}=\sqrt{12^2\cdot (x^{18})^2}

Simplify, we have,

=\sqrt{12^2\cdot (x^{18})^2}=12x^{18}

Thus, The simplified form of \sqrt{144x^{36}} is 12x^{18}

6 0
3 years ago
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Help with the following problem please
Effectus [21]
Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5

By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1

Area of outer circle                  = \pi R^2=\pi7^2=49\pi
Area of large shaded circle      = \pi x^2=\pi5^2=25\pi
Area of 4 small shaded circles = 4\pi r^2=4\pi1^2=4\pi
Total area of shaded circles     =25\pi+4\pi=29\pi

Shaded area as a fraction of that of the outer circle 
=\frac{29\pi}{49\pi}=29/49

3 0
3 years ago
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