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3 years ago

State 2 advantages of laptops over desktop computers

Computers and Technology

2 answers:

PSYCHO15rus [73]3 years ago

8 0

1. Laptops are portable
2. Laptops take less space

Tcecarenko [31]3 years ago

7 0

Answer:

portable ,and they have accessories such as a track pad, a keyboard, a microphone, and a web camera.

Explanation:

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Consider the following code:

ycow [4]

Answer:

The num >= 0 test condition is not correct

Explanation:

The line would lead to the printing of "Your entered: " + str(num) repeatedly without stopping.

The while loop checks the condition that the "num" variable is less than zero. This condition will always be true as there is no means of resetting the value after initially inputting the value that is less than zero.

4 0

3 years ago

Most file managers include a way to create a folder through the save dialog box. true or false?

Illusion [34]

Answer:

false because most of the file managers just keep Everything organized by dates, years, and everything like that

Explanation:

5 0

2 years ago

Your location has been assigned the 172.149.254.0 /24 network. You are tasked with dividing the network into 13 subnets with the

ira [324]

The subnet mask would be a 32-bit integer which is formed by assigning the host bits to all 0's and the networking bits to so many 1's.
In this method, the subnetting separates the IP address between host and network addresses.
The subnet mask covers an IP address with its 32-bit number, thus the term "mask".

Given:

Network IP address $\bold{= 172.149.254.0 /24}$

Subnet numbers $\bold{= 13}$

Calculating the borrow bits:

$\to \bold{= ceil(\log_{2} 13) = 4 \ bits}$

Calculating the dotted decimal value for the subnet mask:

$\to \bold{11111111.11111111.11111111.00000000}\\\\\to \bold{255.255.255.240}\\\\$

The additional bits which will be needed to mask the subnet mask that is = 4.

Learn more: brainly.com/question/2254014

4 0

3 years ago

a limited-access expressway. A)allows vehicles to enter or exit only at certain place.B) does not permit trucks or buses.C)has n

zepelin [54]

Hello babe I just wanted to say hello

3 0

3 years ago

Write a program that converts a number entered in Roman numerals to decimal. your program should consist of a class, say, Roman.

arlik [135]

Answer:

The code is given below in Java with appropriate comments

Explanation:

import java.util.*;

public class RomantoDecimal {

public static void main(String[] args)

{

Scanner SC = new Scanner(System.in);

RomantoDecimal r = new RomantoDecimal();

System.out.println("Enter a Roman number :");

// INPUT A ROMAN NUMBER

String rNum = SC.next();

// CALL convertToDecimal FOR CONVERSION OF ROMAN TO DECIMAL

r.convertToDecimal(rNum);

}

// M=1000, D=500, C=100, L=50, X=10, V=5, I=1

public void convertToDecimal(String roamNo)

{

int number = 0;

// TEACK EACH DIGIT IN THE GIVEN NUMBER IN REVERSE ORDER

for (int i = roamNo.length() - 1; i >= 0; i--)

{

// FIND OUT WHETHER IT IS 'M' OR NOT

if (roamNo.charAt(i) == 'M')

{

if (i != 0)

{ // CHECK WHETHER THERE IS C BEFORE M

if (roamNo.charAt(i - 1) == 'C')

{

number = number + 900;

i--;

continue;

}

number = number + 1000;

}

// FIND OUT WHETHER IT IS 'D' OR NOT

else if (roamNo.charAt(i) == 'D')

{

if (i != 0)

{

// CHECK WHETHER THERE IS C BEFORE D

if (roamNo.charAt(i - 1) == 'C')

{

number = number + 400;

i--;

continue;

}

number = number + 500;

}

// FIND OUT WHETHER IT IS 'C' OR NOT

else if (roamNo.charAt(i) == 'C')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'X')

{

number = number + 90;

i--;

continue;

}

number = number + 100;

}

else if (roamNo.charAt(i) == 'L')

{

if (i != 0)

{

if (roamNo.charAt(i) == 'X')

{

number = number + 40;

i--;

continue;

}

number = number + 50;

}

// FIND OUT WHETHER IT IS 'X' OR NOT

else if (roamNo.charAt(i) == 'X')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'I')

{

number = number + 9;

i--;

continue;

}

number = number + 10;

}

// FIND OUT WHETHER IT IS 'V' OR NOT

else if (roamNo.charAt(i) == 'V')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'I')

{

number = number + 4;

i--;

continue;

}

number = number + 5;

}

else // FIND OUT WHETHER IT IS 'I' OR NOT

{

number = number + 1;

}

}// end for loop

System.out.println("Roman number: " + roamNo + "\nIts Decimal Equivalent: " + number);

}

3 0

3 years ago