Answer:
its easy
Explanation:
there are are 5 main rules
in binary there are 2 number 0 and 1
0 + 0 = 0
0 + 1 = 1
1+0=1
1+1=0 carry 1
e . g
1 1 1
1 0 1 0 1 0
+ 1 1 0 0 1 0
-------------------------
1 1 1 1 1 0 0
*in bold are the ones that you need to carry.
in decimal there are 10 possible numbers 0- 9
when you do 1 + 9 it becomes 10, this can be done easily, however if you do 1 + 9 in a table like above, you will get 0 for the first column and you will carry 1 to the next column .
in binary is the same idea but using on 2 numbers 1 and 0
e.g
1
1
+ 9
----------
1 0
*in bold are the ones that you need to carry.
hope it helps and good luck in your exam.
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
Answer:
Explanation:
Let's do this in Python. We will loop through 4 times, each of the loop would compute the dividend, store it as string in a result variable and finally print the result on the same line:
def divide_4_times(user_num, x):
result = ''
for i in range(4):
user_num /= x
result += (' ' + str(user_num))
print(result)
Company ABC should use passwords but also have them use a code so that not just anyone can get in. Kinda like facebook.
