it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.
Let h(t) represent the height of the ball at time t.
Given that the height is given by:
h(t) = -16t² + 80t + 40
1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:
40 = -16t² + 80t + 40
16t² - 80t = 0
t(t - 5) = 0
t = 0 or t = 5
Hence it takes 5 seconds to reach a height of 40 ft.
2) The maximum height is at h'(t) = 0,
h'(t) = -32t + 80
-32t + 80 = 0
32t = 80
t = 2.5
It takes 2.5 seconds to reach maximum height.
Find out more at: brainly.com/question/11535666
Answer:
Length = 2w
Width= w
2w times w= 241
2W^2=241
Divide by 2
W-^2=121
Sq rt each side
W-= 11 cuz 11 times 11=121
hope this helped
If it did, brainliest would be appreciated!
2 3/4 divided by 1/4
is
2 3/4 multiplied by 4/1
which is (2+3/4)*4 = 2*4 + 3/4*4 = 8+3 =<em>11</em>
Step-by-step explanation:
The answer is B
Answers is B
