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svlad2 [7]
3 years ago
15

Please help with this

Mathematics
1 answer:
wlad13 [49]3 years ago
4 0

Answer:

check pdf

Step-by-step explanation:

Download pdf
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Find 4ab when (a+b)=15 and (a-b)=12
Volgvan
A + b = 15 ..... eq 1
a – b = 12 ...... eq 2

So a = 15 – b
Substitute in eq 2 :

15 – b – b = 12
15 – 2b = 12
–2b = 12 – 15
b = 1.5

So a = 15 – 3/2 = 13.5

4ab = 4 x 13.5 x 1.5 = 81
4 0
3 years ago
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Yeah I know pretty easy I’m just lost so can anyone help put
alekssr [168]

Options A,C,D and E are the correct answers

5 0
3 years ago
Can you plese help me
Luba_88 [7]

Answer:

I think Output relationship is 3,-2,3,-2 and Input relationship is -2,3,1,0.

7 0
2 years ago
EXTRA POINTS- find the value of x and the measure of each angle
Ierofanga [76]

Answer:

4.

x=15

angles

5x-24 = 51

3x+6 = 51

5.

x=58

angles

2x = 116

x+6 = 64

Step-by-step explanation:

5 0
2 years ago
How much heat is required to raise the temperature of
Elina [12.6K]

Answer:

The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .

Step-by-step explanation:

Given as :

The mass of liquid water = 50 g

The initial temperature = T_1 = 15°c

The final temperature = T_2  = 100°c

The latent heat of vaporization of water = 2260.0 J/g

Let The amount of heat required to raise temperature = Q Joule

Now, From method

Heat = mass × latent heat × change in temperature

Or, Q = m × s × ΔT

or, Q =  m × s × ( T_2 - T_1 )

So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )

Or, Q =  50 g × 2260.0 J/g × 85°c

∴   Q = 9,605,000  joule

Or, Q =  9,605 × 10³ joule

Or, Q = 9605 kilo joule

Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer

4 0
3 years ago
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