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3 years ago

A triangle with two congruent sides is called a(n) triangle.

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

6 0

Answer:

ISOSCELES!!!!!!!!!!!!!!!!!!!!!!111

Step-by-step explanation:

mars1129 [50]3 years ago

4 0

A triangle with 2 congruent sides is an ISOSCELES triangle.

Answer: Isosceles

FYI: A triangle with 3 congruent sides is an equilateral triangle.

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A musical group is putting on show at the theatre. They collected $880 from 120 people attending. The price of an adult ticket i

pantera1 [17]

Answer: 60 adults and 60 students

Step-by-step explanation:

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3 years ago

Which statement compares the two numbers correctly?

slamgirl [31]

Answer:

Step-by-step explanation:

So, we have-

(6 x .1) + (3 x .01) + (2 x .001)

So, we will solve inside of the parenthesis first.

6 x .1 = .6

So, we got that settled next-

3 x .01 = .03

We got that settled last-

2 x .001 = .002

Lastly, we add them all.

.6 + .03 + .002 = .632

Now we compare.

.632 > .629

So, there is your answer!

Hope this helps!

7 0

3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

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1 year ago

16. Write the inequality that is shown on the graph.

TiliK225 [7]

Answer: 5<x<9

Step-by-step explanation:

Graph is from 5 to 9, not including 5 and 9. Let's say x is all the values from 5 to 9, not including 5 and 9.

So, answer is 5<x<9

3 0

1 year ago

help me please!!!!!! I really need help

IRINA_888 [86]

Answer:

Part A: hx2=a

Part B: 5hours

Step-by-step explanation:

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3 years ago