From left to right, the answers are: 152, D(line e), C(obtuse), 44 degrees.
Now I feel guilty and sleezy. Giving answers alone without explanations
is something I almost never do, because it doesn't help anybody do
anything but cheat. But it's all I have time for right now. If a mod comes
along and decides to delete this because of no explanations, then let him
delete it. It'll serve us right, you and me both.
The distance between starting and ending point is 34 miles.
Step-by-step explanation:
Given,
Car moves 16 miles to north then 30 mile to east.
It forms a right angle triangle.
The straight line distance from starting to ending point represents hypotenuse.
To find the distance between starting and ending point.
Formula
By <em>Pythagoras theorem,</em>
h² = b²+l² where h is the hypotenuse, b is base and l is the another side.
Taking, b=16 and l=30 we get,
h² = 16²+30²
or, h = 
or, h = 
= 34
Hence,
The distance between starting and ending point is 34 miles.
Answer:
y = (-1/5)x - 9
Step-by-step explanation:
15y = -3x - 135
Divide both sides by 15
y = (-1/5)x - 9
<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.
Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).
The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or
sqrt(25(2)+25(2)) = sqrt(100) = 10.
</span>
