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3 years ago

Can someone help it’s for a test

Mathematics

2 answers:

Irina-Kira [14]3 years ago

7 0

Answer: G

Step-by-step explanation: She has 5 pink bows, 1 blue bow, and 4 purple.

You add them all for a total of 10 and we need to find the chance she pulls a purple bow.

The chance of her pulling one is 4/10

But we need to simplify which would be 2/5

netineya [11]3 years ago

5 0

Answer:

2/5

because 4/10 simplified by 2 is 2/5

..............

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Consider this system of equations:

alexandr1967 [171]

"For which value of k does the system have no real number solutions?"
The answer is 4, because 4+4≠16.

"For which value of k does the system have one real number solution?"
The answer is -0.25, because the linear line because tangent with the parent function.

"For which value of k does the system have two real number solutions?"
The answer is 2, because the linear function intercepts the parent function 2 times.

- i hope these are the answers you are looking for.

5 0

3 years ago

If two sides of a triangle are 10 units and 13 units,a possible third side for the could be?

IrinaK [193]

Pythagorean theorem:

a^2+b^2=c^2

substitute:

10^2+13^2=c^2

simplify:

100+169=c^2

simplify:

269=c^2

take the square root:

c=16.4

The answer is 16.4

5 0

4 years ago

How to write 76. 100 in word form

joja [24]

Seventy-six and one tenth

5 0

3 years ago

A swimming pool is in the shape of a rectangular prism. the pool is 4 feet deep. its length is 4 times its width. the volume of

makvit [3.9K]

First you will have to use the equation length*width*height. The just plug in 4 for the height, then since the length is 4 times longer plug in 4x, and the width would just be x. SO your equation would be 4*4x*x=6400 ft^3. Then foil it out to get 16x^2=6400, then square root 6400 which will give you80, then divide by 16 so x=5 feet^3. That is your width but you length is 4 times that amount. So for length just do 4(5)=20 feet^3

7 0

3 years ago

1. Approximate the given quantity using a Taylor polynomial with n3.

Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

$f(x) = x^{1/4}$

The n-th order Taylor polynomial for function f with its center at a is:

$p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}$

As n = 3 So,

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}$

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}$

$p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} } (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} + (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}$

$p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} } (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} + (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}$

$p_{3} (x)$ = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6

(0.0000018522752) (x-81)³

$p_{3} (x)$ = 0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

(x-81)³ + 2.25

Hence approximation at given quantity i.e.

x = 94

Putting x = 94

$p_{3} (94)$ = 0.0092592593 (94) - 0.000042866941 (94 - 81)² +

0.00000030871254 (94-81)³ + 2.25

= 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +

2.25

= 0.87037 03742 - 0.000042866941 (169) +

0.00000030871254(2197) + 2.25

= 0.87037 03742 - 0.007244513029 + 0.0006782414503 + 2.25

$p_{3} (94)$ = 3.113804102621

Compute the absolute error in the approximation assuming the exact value is given by a calculator.

Compute $\sqrt[4]{94}$ as $94^{1/4}$ using calculator

Exact value:

$E_{a}$ (94) = 3.113737258478

Compute absolute error:

Err = | 3.113804102621 - 3.113737258478 |

Err (94) = 0.000066844143

If you round off the values then you get error as:

|3.11380 - 3.113737| = 0.000063

Err (94) = 0.000063

If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

Err (94) = 0.0001

4 0

3 years ago