What proportion of a normal distribution is located between z = 1.00 and z = 1.50?

Mathematics

1 answer:

lesya692 [45]3 years ago

4 0

Answer:

0.092 is the required proportion.

Step-by-step explanation:

We are given the following in the question:

A normal distribution.

We have to find the proportion of data lying between z = 1.00 and z = 1.50.

P(between z = 1.00 and z = 1.50)

$P(.001 \leq z \leq 1.50)\\= P(z \leq 1.50) - P(z < 1.00)\\= 0.933 - 0.841 = 0.092 = 9.2\%$

Thus, 0.092 is the proportion of data located between z = 1.00 and z = 1.50.

You might be interested in

Please help on this question

Paul [167]

Answer:

6912xy^8

Step-by-step explanation:

The 9th term is the next-to-last term, where the left term of the binomial is raised to the first power, the right term of the binomial is raised to the 8th power (9-1=8), and the multiplier is 9C8 = 9!/(8!·1!) = 9. This product is ...

9·(3x)^1·(-2y)^8 = 6912xy^8

8 0

3 years ago

Don't be childish I will report thanks

Semenov [28]

Answer:

what do you mean childish?.. anyway your answer is

-2| 3 - 6 |

= -6

happy to help!

5 0

2 years ago

Read 2 more answers

HELP!

artcher [175]

Answer:

B.Obtuse

as shown in the pictures that you put the angel is obtuse

6 0

2 years ago

A square with side x is changing with time where x(t)=3t+1. What is rate of change of the area of the square when t=2 seconds.

GuDViN [60]

Answer:

Rate of change of the area of the square is 42 units at t = 2.

Step-by-step explanation:

We note that the area of the square is given by: $A(x) = x^2$ but we aim to find $\frac{dA}{dt}$ . But we can use the chain rule to pull out that dA/dt. Doing so gives us: