Can someone help me with this. Will Mark brainliest.
1 answer:
You might be interested in
Step-by-step explanation:
Hey there!
Follow the steps to get answer.
- Use one point formula and find 1st equation.
- After that you find the slope of second equation.
- Use the condition of perpendicular lines and find the slope of first equation.
- Put slope value of equation in equation (i) and simplify them to get equation.
The equation of a line passing through point (2,3) is;
(y-3)= m1(x-2).......(i).
Another equation is;
2nd equation..
Now, From equation (ii)
We have;
Comparing equation (ii) with y = mx+c.
We get;
Slope = -1/2.
For perpendicular lines,
Therefore the slope is 2.
Put value of slope (m1) in equation (i). We get;
Simplify them to get equation.
Therefore the required equation is y = 2x-1.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Slope-intercept form:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0)
You need to find "m" and "b".
If you look at the graph, when x = 0, y is 1, so the y-intercept is 1.
y = mx + 1
To find "m", you can use the slope formula and find two points on the graph and plug it in, or you can use this:
Rise is the number of units you go up(+) or down(-)
Run is the number of units you go to the right.
If you look at the graph, from each point you go up 1 unit, and to the right 1 unit. So your slope is or 1
y = 1x + 1
y = x + 1