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nikklg [1K]
3 years ago
10

What is the singular multiplier for 35%

Mathematics
1 answer:
BaLLatris [955]3 years ago
8 0

The singular is the one and only, so it's 35/100 simplify it= 7/20

So the multiplier is the first digit of the fraction<u><em> 7</em></u>/20

<h2>So the answer is 7</h2>
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6. Write an equation of a line that is Parallel to the line: y = 3x -3
jeka94

Answer:

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Step-by-step explanation:

We need to find the Equation of the line parallel to the given equation of line . The given equation of the line is ,

\rm\implies y = 3x - 3

<u>Slope </u><u>Intercept</u><u> Form</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = mx + c

where ,

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Therefore , the Slope of the line is 3 . Let the parallel line passes through ( 3,3) . We know that the parallel lines have same slope . Therefore the slope of the parallel line will also be 3 .

<u>Using</u><u> point</u><u> slope</u><u> form</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y - y_1 = m ( x - x_1)  \\\\\rm\implies y - 3 = 3( x - 3 ) \\\\\rm\implies y -3 = 3x -9 \\\\\rm\implies 3x -y -9+3=0\\\\\rm\implies \boxed{\rm\red{ 3x -y -6=0}}

3 0
3 years ago
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Read 2 more answers
Please hurry. Solve the equation
Lelu [443]

The value of x is 5\sqrt[3]{25}.

Solution:

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Subtract 8 from both side of the equation.

8-3 \sqrt[5]{x^{3}}-8=-7-8

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Divide by –3 on both side of the equation.

$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}

\sqrt[5]{x^{3}}=-5

To cancel the cube root, raise the power 5 on both sides.

(\sqrt[5]{x^{3}})^5=(-5)^5

x^3=3125

To find the value of x, take square root on both sides.

\sqrt[3]{x^3}=\sqrt[3]{25}

x=5\sqrt[3]{25}

Hence the value of x is 5\sqrt[3]{25}.

5 0
3 years ago
What is the approximate volume of the cylinder?
Delicious77 [7]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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cluponka [151]

Step-by-step explanation:

Equ of line -

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y=2/3x + 3.67

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3 years ago
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