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Mazyrski [523]
2 years ago
12

At the end of anaphase 11, how many chromatids are on each side of the cell?

Biology
1 answer:
Snezhnost [94]2 years ago
7 0

Chromosomes condense. Metaphase II: Chromosomes line up at the metaphase plate. Anaphase II: Sister chromatids separate to opposite ends of the cell. Telophase II: Newly forming gametes are haploid, and each chromosome now has just one chromatid
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For sample A, A=17.7 %, T=17.7 %, G=32.30%, C=32.30%

For sample B, A= 28.9%, T=28.9%, G= 21.10%, C= 21.10%

Explanation:

The composition of nitrogenous bases in DNA is calculated using the suggestions proposed by the results of the experiment performed by Erwin Chargaff.

He found that in a DNA sample the composition of purine to pyrimidine is 1:1. This indicates that the amount of purine equals pyrimidine. This can be presented as purines + pyrimidines= 100. Also, adenine binds thymine and cytosine binds guanine.

In the given question,  

<u>For sample A </u>

A= 17.7 %, Therefore, thymine will be = 17.7 %,

A+T= 35.40%

Now, G+C=100- 35.40%

G+C= 64.60%

content of G= 64.60/2= 32.30%

content of C= 32.30%

<u>For sample B </u>

T=28.9%, A will be= 28.9%

A+T= 57.80%

G+C=100-57.80%

G+C= 42.20%

Thus content of G will be= 42.20/2=21.10

content of C= 21.10%

Thus,  

For sample A, A=17.7 %, T=17.7 %, G=32.30%, C=32.30%

For sample B, A= 28.9%, T=28.9%, G= 21.10%, C= 21.10%

6 0
3 years ago
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