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My name is Ann [436]
3 years ago
10

(c) Write the balanced neutralization reaction and calculate the volume in mL of a 1.420 M NaOH solution required to titrate 25.

00 mL of a 5.400 M H2SO4 solution
Chemistry
1 answer:
boyakko [2]3 years ago
8 0

Answer:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

190.14 mL of the NaOH solution would be required.

Explanation:

The balanced reaction is:

  • 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

Now we <u>calculate how many H₂SO₄ moles are there in 25.00 mL of a 5.400 M solution</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / liters
  • Moles = Molarity * liters
  • 25.00 mL * 5.400 M = 135 mmol H₂SO₄

Now we <u>convert H₂SO₄ moles into NaOH moles</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 135 mmol H₂SO₄ * \frac{2mmolNaOH}{1mmolH_2SO_4} = 270 mmol NaOH

Finally we <u>calculate the volume of a 1.420 M solution that would contain 270 mmoles</u>:

  • Molarity = moles / liters
  • liters = moles / molarity
  • 270 mmol / 1.420 M = 190.14 mL
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