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Gekata [30.6K]
3 years ago
9

Find all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π.

Mathematics
1 answer:
jarptica [38.1K]3 years ago
5 0
Hello : 
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions : 
2x= x +2k</span>π    or x= π -x +2kπ ..... k in : Z
x = 2kπ  or : x = π/2 + kπ 
but :
 <span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are : 
</span>k = 0 : x=0    , x= π/2
k=1 : x=2 π    , x=3π/2
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Answer:

  split the number into equal pieces

Step-by-step explanation:

Assuming "splitting any number" means identifying parts that have the number as their sum, the maximum product of the parts will be found where the parts all have equal values.

We have to assume that the number being split is positive and all of the parts are positive.

<h3>2 parts</h3>

If we divide number n into parts x and (n -x), their product is the quadratic function x(n -x). The graph of this function opens downward and has zeros at x=0 and x=n. The vertex (maximum product) is halfway between the zeros, at x = (0 + n)/2 = n/2.

<h3>3 parts</h3>

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Step-by-step explanation:

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