This is a problem of fundamental counting principle. In a
sequence of events, the total possible number of ways all events can performed
is the product of the possible number of ways each individual event can be
performed. So here there is one car in each place so there 4 possible
cars to get the 1st place, 3 possible car for the 2nd
place, 2 possible cars for 3rd place and 1 for the 4th
place. The 4x3x2x1 = 24 different order
Answer:
28.07° ; 70.53° ; 53.13° ; 36.87°
Step-by-step explanation:
Using PYTHAGORAS RULE :
IMAGE 1:
value of cos α equals :
cos α = Adjacent / Hypotenus
cos α = 15 / 17
cos α = 0.88235
α = cos^-1 (0.88235)
α = 28.07°
IMAGE 2:
sin β = Opposite / Hypotenus
sin β = 14√2 / 21
sin β = 0.9428
β = sin^-1(0.9428)
β = 70.53°
IMAGE 3:
From trigonometry :
cot = 1 / tan
Tan = Opposite / Adjacent
Therefore, Cot = Adjacent / Opposite
cot γ = 3/4
cot γ = 0.75
γ = cot^-1 (0.75)
γ = 53.13°
IMAGE 4:
tan α = Opposite / Adjacent
tan α = 15 / 20
tan α = 0.75
α = tan^-1 (0.75)
α = 36.87°
The answer (im pretty sure) is: 10 2/5
V = x³ - 6x²y + 12xy² - 8y³
V = (x - 2y)³
= (x - 2y)(x - 2y)(x - 2y) ( expand first pair of factors )
= (x² - 4xy + 4y²)(x - 2y) ( multiply terms in first by terms in second )
= x³ - 4x²y + 4xy² - 2x²y + 8xy² - 8y³ ( collect like terms )
= x³ - 6x²y + 12xy² - 8y³
